Answer:
Vb = 0.334 m/s
Va = -1.265 m/s
Vc = 1.424 m/s
Explanation:
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Initial momentum = 255(2) – 242.5(1.5) = 146.25
Final momentum = 255Va + 290Vb + 242.5 Vc = 146.25
Vb - Va = 0.8(2) = 1.6
Vc - Vb = 0.8(1.5) = 1.2
Va = Vb -1.6
Vc = Vb + 1.2
255(Vb -1.6) + 290Vb + 242.5(Vb + 1.2) = 146.25
255 Vb – 408 + 290 Vb + 242.5 Vb + 291 = 146.25
787.5 Vb = 263.25
Vb = 0.334 m/s
Va = Vb -1.6 = 0.334 – 1.6 = -1.265 m/s
Vc = Vb + 1.2 = 0.224 + 1.2 = 1.424 m/s
Answer:
Comparison has been made.
Explanation:
Consider perfectly inelastic collision.Two masses of m1 and m2 with initial velocities u1 and u2 before colliding, stick together after collision and move with common speed v. then according to the rule of momentum preservation
m1u1+m2u2= (m1+m2)v

If u1 and u2 are known the final common velocity can be determined
Initial kinetic energy is

The collion here is perfectly inelastic this means kinectic energy is not conserved. Therefore, initial kinectic energy is not equal to final kinectic.

Answer:
a)
b)
.
Explanation:
Given that
Boyle's law
P V = Constant ,at constant temperature
a)
Given that


We know that for PV=C

Now by putting the values
PV= 50 x 0.106

Where P is in KPa and V is in 
b)
PV= C
Take ln both sides
So 
lnP + lnV =lnC ( C is constant)
By differentiating

So

When P= 50 KPa

It indicates the slope of PV=C curve.
It unit is
.
Or we can say that
.
<span>The atom becomes positively charged.
When you add electrons to a neutral atom, it is no longer a neutral atom, it has a negative change and is an anion. When you take away electrons from a neutral atom, it is no longer a neutral atom- it becomes a positive atom, and is a cation.</span>