Answer:
the answer is
Explanation:For equilibrium
Weight = Tension
mg=T
∴T=4×3.1π=12.4πN (as can be inferred from the question)
Y=
△l/l
T/A
=
1000
0.031
/20
12.4π/π(
1000
2
)
2
=
4×0.031
12.4×20×1000×(1000)
2
=2×10
12
N/m
2
Answer:
The average induced emf is 29.06 V
Explanation:
Given;
radius of the circular loop, r = 12.0 cm = 0.12 m
magnetic field strength, B = 1.8 T
time interval = 2.8 ms = 0.0028 s
Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

where;
B is magnetic field
A is area
t is time
substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

Therefore, the average induced emf is 29.06 V
Answer:
The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.
Explanation:
Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:
At the top of a round hill

At the foot of a round hill
