Let’s pick a paperback and a hardback
There are 4 x 6 possible choices
Now pick any three of the remaining 8 books
8C3 = 56
This means there are 4 x 6 x 56 = 1344 selections of 5 books that will contain at least one paperback and one hardback
8C3 means picking 3 from 8 without worrying about order
8C3 = 8 x 7 x 6 / (3 x 2 x 1) = 56
Simply just think of two numbers that multiply to -48.
That's -12 and 4.
Does it add up to 8: -12 + 4 = 4 -12 = -8
It doesn't, so we revert the sign.
12 and -4 Product = 12*-4 = -48
Addition = 12 + -4 = 12 -8 = 8. Correct.
The answer is 12 and -4.
To answer this question, an assumption must be made, that Eva spends 8 hours a day working. If this is the case, then Eva will complete jobs w, x, and v on day one, for a total of six hours. Since the next job (y) requires 4 hours, she will spend two hours working that day, leaving 2 more hours to go on that job. The next day she will spend 2 hours finishing job y, completing it, and finish the longest job z (hours) that day. This means she had 4 jobs on day one, and 2 jobs on day 2 for and average of 3 jobs per day.
This answer assumes an 8 hour work day, and that Eva can start a job she cannot finish that day.
Yo sup??
the truth table value for p implies q is true and it's given that q is true
Hence p is sometimes true.
Hope this helps
I can’t see the questions clearly. Could you retake the picture again?