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Nataly [62]
2 years ago
7

On May 1, 2019, Joe Hill is considering one of the following newly issued 10-year AAA corporate bonds. Description Coupon Price

Callable Call Price Wildwood, due May 1, 2027 5.0% $100 noncallable NA Asbury, due May 1, 2027 5.4% $100 currently callable $102 If interest rates are expected to rise, then Joe Hill should __________. Multiple Choice prefer the Wildwood bond to the Asbury bond The answer cannot be determined from the information given. be indifferent between the Wildwood bond and the Asbury bond prefer the Asbury bond to the Wildwood bond
Business
1 answer:
wolverine [178]2 years ago
8 0

When interest rates are expected to rise, then Joe Hill should D. prefer the Asbury bond to the Wildwood bond.

<h3>What is a bond?</h3>

A bond simply means a form of security that is used in mutual funds and private investing.

In this case, when interest rates are expected to rise, then Joe Hill should prefer the Asbury bond to the Wildwood bond. This is important to prevent loss.

Learn more about bond on:

brainly.com/question/25596583

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Explanation: The study of microeconomics helps the decision makers to analyze and determine how the productive resources are allocated for various goods and services. It also helps in solving the producers' dilemma of what to produce, how much to produce and for whom to produce. <33

7 0
3 years ago
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A company is considering buying a new piece of machinery. A 10% interest rate will be used in the computations. Two models of th
JulsSmile [24]

Answer:

Machine I

capitalized cost:  230,271.28

EAC: $ 27,047.58

Machine II

EAC:  $ 27,377.930  

As Machine I cost per year is lower it is better to purchase that one.

Annual deposits to purchase Machine I in 20 years: $ 1,396.770  

return of machine I with savings of 28,000 per year: 10.51%

Explanation:

WE calculate the present worth of each machine and then calculate the equivalent annual cost:

MACHINE 1

Operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 18,000

time 20

rate 0.1

18000 \times \frac{1-(1+0.1)^{-20} }{0.1} = PV\\  

PV $153,244.1470  

Salvage value:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $20,000.0000  

time   20.00  

rate  0.1

\frac{20000}{(1 + 0.1)^{20} } = PV  

PV   2,972.87  

Total: -80,000 cost - 153,244.15 annual cost + 2,972.87 salvage value:

Total: 230,271.28

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

Present worth  $(230,271.28)

time 20

rate 0.1

-230271.28 \div \frac{1-(1+0.1)^{-20} }{0.1} = C\\  

C -$ 27,047.578  

Fund to purchase in 20 years:

FV \div \frac{(1+r)^{time} -1}{rate} = C\\  

FV  $80,000.00  

time 20

rate 0.1

80000 \div \frac{(1+0.1)^{20} -1}{0.1} = C\\  

C  $ 1,396.770  

IF produce a 28,000 savings:

we must solve using a financial calcualtor for the rate at which the capitalized cost equals 28,000

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $230,271.28  

time 20

rate 0.105126197

230271.28 \div \frac{1-(1+0.105126197287798)^{-20} }{0.105126197287798} = C\\  

C  $ 28,000.000  

rate of 0.105126197 = 10.51%

<u>Machine II</u>

100,000 cost

25,000 useful life

15,000 operating cost during 10 years

20,000 for the next 15 years

Present value of the operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 15,000

time 10

rate 0.1

15000 \times \frac{1-(1+0.1)^{-10} }{0.1} = PV\\  

PV $92,168.5066  

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 20,000

time 15

rate 0.1

20000 \times \frac{1-(1+0.1)^{-15} }{0.1} = PV\\  

PV $152,121.5901  

in the timeline this is at the end of the 10th year we must discount as lump sum for the other ten years:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $152,121.5901  

time   10.00  

rate  0.1

\frac{152121.590126167}{(1 + 0.1)^{10} } = PV  

PV   58,649.46  

salvage value

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $25,000.0000  

time   25.00  

rate  0.1

\frac{25000}{(1 + 0.1)^{25} } = PV  

PV   2,307.40  

Total cost: 100,000 + 92,168.51 + 58,649.46 - 2,307.40 = $248,510.57

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $248,510.57  

time 25

rate 0.1

248510.57 \div \frac{1-(1+0.1)^{-25} }{0.1} = C\\  

C  $ 27,377.930  

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4 years ago
Masse Corporation uses part G18 in one of its products.
DaniilM [7]

Answer:

Masse Corporation

1. The effect on the company's total net operating income of buying part G18 from the supplier rather than continuing to make it inside the company is an additional cost of $47,100.

2. Masse Corporation should continue to produce the part in-house.  The "Make" alternative is better.

Explanation:

a) Data and Calculations:

Units of part G18 needed yearly = 17,100

Costs of production:

Direct materials      $4.30

Direct labor              5.00

Variable overhead  8.00

Supervisor's salary 8.70

Total variable costs= $26 * 17,100 = $444,600

Avoidable general overhead cost =    $23,100

Total avoidable costs =                      $467,100

Outside supplier's offered price for the part = $32 each

Total cost for the outside supply = $547,200 ($32 * 17,100)

Unavoidable fixed costs:

Depreciation of special equipment 9.30

Allocated general overhead 6.30 * 17,100 = $107,730

Unavoidable cost = $84,630 ($107,730 - $23,100)

b) The effect on the company's total net operating income of buying part G18 from the supplier rather than continuing to make it inside the company is an additional cost of $47,100 ($547,200 - $467,100 - $33,000).

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