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1 year ago

H = ac + mn solve for n

Mathematics

1 answer:

notka56 [123]1 year ago

6 0

Answer:

$n = \frac{h - ac}{m}$

Step-by-step explanation:

$h = ac + mn$

$mn = h - ac$

$n = \frac{h - ac}{m}$

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I REALLY BEED HELP RN I FORGOT HOW TO DO THIS

Gekata [30.6K]

Answer:

Step-by-step explanation:

Because u need to find the LCD and the LCD of 4 and 7 is 28

4 0

3 years ago

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Describe the end behavior of the graph of g(x)=3x^2-2x

ivanzaharov [21]

Answer:

x approaches ∞→ f(x) approaches ∞

x approaches -∞→ f(x) approaches ∞

Step-by-step explanation:

This graph is a parabola. The parent function end behavior is as x approaches ∞→ f(x) approaches ∞ and when x approaches -∞→ f(x) approaches ∞. There are no reflections made so the end behavior is the same as the parent function.

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3 years ago

Find each quotient. Round your answer to the nearest hundred 7.93 divided by 4

Law Incorporation [45]

1.98
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3 years ago

PLEASE HELP ME =(((((((((((((((((((((((

artcher [175]

Answer:

The answer is

$y = - 5x - 2$

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, The is what the slope formula is ☟

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 2 - 3}{0 - ( - 1)} = \frac{ - 5}{ \: \: \: 1} = - 5$

➋Second: We find the y-intercept.

$y = mx + b \\ 3 = - 5( - 1) + b \\ 3 = 5 + b \\ \frac{ - 5 = - 5 \ \ \: \: \: \: \: \: }{ - 2 = b}$

➌Third: Plug in.

$y = - 5x - 2$

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3 years ago

Which statement describes the behavior of the function f (x) = StartFraction 2 x Over 1 minus x squared EndFraction?

Daniel [21]

Answer:

Second option: the graph approaches 0 as x approaches infinity.

Explanation:

The function f(x) is:

$f(x)=\frac{2x}{1-x^2}$

When x approach infinity the term x² grows rapidly (more rapid than x), thus 1 - x², which is in the denominator will decrease, become a large negative more rapid than the x in the numerator. Thus you can expect that the function approaches zero.

To prove that in a more analytical way, divide both numerator and denominator by x and simplifiy:

$\lim_{x \to \infty} \frac{2x}{1-x^2}\\\\ \lim_{x \to \infty} \frac{2x/x}{(1-x^2)/x}\\\\ \lim_{x \to \infty} \frac{2}{1/x-x}\\\\\lim_{x \to \infty} \frac{2}{0-x}\\ \\ \lim_{x \to \infty} \frac{2}{-x}\\ \\ \lim_{x \to \infty} -\frac{2}{x}=0$

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3 years ago

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