All categories

2 years ago

Find the area of each parallelogram below.

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

7 0

Answer:

area of first

parallelogram

= 25x8

=200m^2

area of second

parallelogram

12x7

=84f^2

Step-by-step explanation:

I hope it's helpful for you

You might be interested in

Which expressions are equivalent to 3 1/4 - (- 5/8)?

Lady_Fox [76]

Answer:

3.875

Step-by-step explanation:

3 0

3 years ago

Consider a binomial experiment. If the number of trials is increased, what happens to the expected value

Aliun [14]

Answer:

The expected value is an expression of the weighted average and can be taken as the (arithmetic) mean

As the number of trials is increased in a binomial experiment, the expected values obtained, in each of the set of trials continuously tend to the theoretical expected value

Step-by-step explanation:

3 0

3 years ago

I need to know what is the chance the driver still got in an accident

Yakvenalex [24]

Answer:

answer is 35

Step-by-step explanation:

5 0

3 years ago

Helpppp!!!!1

Rzqust [24]

Answer:

$7.76\times 10^6\ \text{inches}$

Step-by-step explanation:

We know that,

$1\ \text{inch}=1.578 \times 10^{-5}\ \text{miles}$

We need to convert 1225 miles to inches. It can be done as follows :

$1\ \text{mile}=\dfrac{1}{1.578 \times 10^{-5}}\ \text{inches}\\\\1225\ \text{miles}=\dfrac{1225}{1.578 \times 10^{-5}}\ \text{inches}\\\\=7.76\times 10^6\ \text{inches}$

So, there are $7.76\times 10^6\ \text{inches}$ in 1225 miles.

3 0

3 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

3 years ago

Find the area of each parallelogram below.​

Find the area of each parallelogram below.