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netineya [11]
3 years ago
7

Solve for X Need help ASAP

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0
X = nine. Seventy five / 9.75!
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If ∠A and ∠B are complementary, find the value of x given that ∠A=3x-2 and ∠B=x+12
xxMikexx [17]

Answer:

x=20 degrees

Step-by-step explanation:

complementary means the angles equal 90 degrees

so ∠A+∠B=90 degrees

∠A=3x-2 and ∠B=x+12

so subsitute

(3x-2)+(x+12)=90

then solve for x

4x+10=90

4x=80

x=20 degrees is your answer

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3 years ago
A. 5/8<br><br> B. -8/5<br><br> C. 8/5<br><br> D. -5/8
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Answer:

A

Step-by-step explanation:

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4 0
3 years ago
Work out the volume of this prism. Write your answer<br> a in cm?<br> 120cm<br> 30cm<br> 20 cm
Tom [10]

Answer:

24,000 cm³

Step-by-step explanation:

5 0
3 years ago
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A jar contains 50 tickets for a drawing. Of these, 7 are winning tickets. What are the odds in favor of drawing a winning ticket
Ainat [17]

Answer: 14%

Step-by-step explanation: 7/50 = 14/100 = .14 = 14%

3 0
3 years ago
An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so n = 40.

The probability that any integrated circuit is defective is 0.01, so \pi = 0.01

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability P(X > 0), or there are no defective integrated circuits, that is probability P(X = 0). The sum of these probabilities is decimal 1. We want to find P(X>0).

P(X > 0) + P(X = 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690

P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

There is a 33.10% probability that there is at least one defective integrated circuit.

3 0
3 years ago
Read 2 more answers
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