7 and 55/10000 which simplifies to 7 and 11/2000
This problem seems it can be worked in a couple different ways. But, I believe arranging the desks in rows of 6 & as many columns as needed depending on the number would be the best solution.
The probability of randomly chosen tall and obese individuals is 0.30.
Firstly complete the given table and find the total of each row and column.
Tall Medium Short Total
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Total 50 104 51 205
We have to find P(Tall | Obese).
P(Tall | Obese) = P(Tall and Obese) / P(Obese)
Now, P(Tall and Obese) = 18 ÷ 205
And, P(Obese) = 60÷205
Substituting the above values,
P(Tall | Obese) = 18÷205/ 60÷205
P(Tall | Obese) = 18/60
P(Tall | Obese) = 0.30
Hence the probability of a tall and obese individual is 0.30.
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