1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igor_vitrenko [27]
2 years ago
8

The equation that describes the change in temperature of a solvent due to a solute is AT6 = i xKb x molality. How much salt woul

d one need to add to 1 kg water to change the boiling temperature
by 5°C? Give your answer in moles. Show your work. (Kb =
0.51°Cfor water and i = 2 for NaCl.

Chemistry
1 answer:
dedylja [7]2 years ago
7 0

4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature

by 5°C.

<h3>What is the moles of Salt required to change the temperature of water by 5°C?</h3>

Based on the given equation, the molality of the solution is calculated as follows:

  • Molality = change in temperature/ Kb × I

Change in temperature = 5 °C

Kb = 0.51

i = 2

Molality = 5/0.51 × 2 = 4.9 molal

Also, Molality = moles/kg of water

Moles of salt = molality × kg of water

Moles of salt = 4.9 × 1 = 4.9 moles.

Therefore, 4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature

by 5°C.

Learn more about molality at: brainly.com/question/9149034

#SPJ1

You might be interested in
How many molecules of carbon dioxide are in 5.61 moles of carbon dioxide (CO2)?
gulaghasi [49]
<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂

6 0
3 years ago
The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

5 0
4 years ago
The bottom of a box has a surface area of 25.0 cm 2 . The mass of the box is 34.0 kilograms. Acceleration due to gravity at sea
Viktor [21]
Pressure given by: 
Pressure=(force)/(area)
Force=Mass*gravitational pull
Mass=34Kg
gravity=9.80

so,
force=34*9.8=333.2
thus;
pressure=333.2/25=13.328=13.3 N/cm^2

Hope this helped :)
5 0
4 years ago
How to do my homework? i’ll give 20 points to anyone who will do it!
tensa zangetsu [6.8K]

what is it ??? ill edit this

3 0
3 years ago
Read 2 more answers
How hydrogen chloride gas is prepared on labrotary by conc sulpheric acid<br> ​
Citrus2011 [14]

Answer:

It is prepared small amounts of hydrogen cloride for uses in the lab.

It can be  "generated in an HCl generator by dehydrating hydrochloric acid with either sulfuric acid or anhydrous calcium chloride."

4 0
3 years ago
Other questions:
  • What is the mass of 1.84 mol NaCl? Give your answer to the correct number of significant figures. (Molar mass of NaCl = 58.44 g/
    10·2 answers
  • The element oxygen, represented by the symbol O, is classified as
    14·2 answers
  • Scientists classify rocks into three different types. What is the main basis for the classification system they chose? color of
    7·2 answers
  • How many oxygen atoms are there in 582 grams of caffeine (CH10N402, 194 g/mol)? Avogadro's Number: 1 mole = 6.02 x 1023 species
    10·1 answer
  • Help me name these molecules please
    14·1 answer
  • Methane is the chief constituent of petroleum fuel <br> A:yes <br> B:no
    10·1 answer
  • I will mark brainliest if all answered or if you don’t want to answer them all please just answer 9-15
    15·1 answer
  • Which of the following correctly represents the radioactive decay of cesium-137?<br><br>​
    14·1 answer
  • a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc
    14·1 answer
  • A gamma ray has a frequency of 2.88 x 1021 Hz. What does this mean?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!