Answer:
I believe it's qualitative and continuous.
Explanation:
The mass percentage of hydrogen in 300 g of sucrose is 9.75%
From the question given above, we were told that:
2 g of sucrose contains 6.50% (ie 0.065) hydrogen
Thus, we can obtain the percentage of hydrogen in 300 g of sucrose as follow:
2 g of sucrose contains 0.065 hydrogen.
Therefore,
300 g of sucrose will contain = = 9.75% of Hydrogen.
Thus, 300 g of sucrose contain 9.75% of Hydrogen.
Learn more: brainly.com/question/16559402
Answer:
The numerical value of K for the reaction is 2.36*10⁻⁴
Explanation:
A chemical equilibrium is a reaction that is never completed, since it occurs simultaneously in both directions (the reactants form products, and in turn, these form reactants again). In other words, it is a dynamic balance. When the concentrations of each of the substances involved (reactants or products) stabilize, that is, they are spent at the same rate as they are formed, chemical equilibrium is reached.
The equilibrium constant (Kc) is expressed as the ratio between the molar concentrations of reactants and products. Its value in a chemical reaction depends on the temperature, so this must always be specified.
Being:
aA + bB ⇄ cC + dD
then the constant Kc is:
In the case of the reaction:
A₂(g) + 3 B₂(g) ⇒ 2 AB₃(g)
The constant Kc is:
Being:
- [AB₃]=7.6*10⁻⁴
- [A₂]= 0.0055
- [B₂]= 0.763
and replacing, you get:
Kc=2.36*10⁻⁴
<u><em>The numerical value of K for the reaction is 2.36*10⁻⁴</em></u>
Answer:
The ¹³C-NMR Spectrum of <em>tert</em>-butyl alcohol will show only two signals.
(i) Signal at around 31 ppm:
This signal towards upfield is for the carbon atoms which are more shielded and are having rich electron surroundings. The height of peak at y-axis shows the number of carbon atoms as compared to other peaks. In this case it is three times the height of second signal hence, it shows that this peak corresponds to three carbon atoms.
(ii) Signal at around 70 ppm:
This signal towards downfield is for the carbon atom which is more deshielded and is having electron deficient surrounding. As compared to the second signal the height of this peaks corresponds to only one carbon. And the deshielded environment shows that this carbon is directly attached to an electronegative element.