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Ket [755]
3 years ago
15

Which of the following elements is a metal in the periodic table​

Chemistry
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

12  My     Magnesium

13 Al Aluminum

19 K Potassium

20 Ca Calcium

Explanation:

I think

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Which of the possible compounds has a mass of 163 grams when
Simora [160]

Answer:

CH4

Explanation:

In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.

Hence we can now say;

If 163 g of the compound contains 6.13 ×10^24 molecules

x g will contain 6.02 × 10^23 molecules

x= 163 × 6.02 × 10^23 / 6.13 × 10^24

x= 981.26 × 10^23/ 6.13 ×10^24

x= 160.1 × 10^-1 g

x= 16.01 g

x= 16 g(approximately)

16 g is the molecular mass of methane hence x must be methane (CH4)

6 0
3 years ago
the balloon is inflated outdoors on a cold day in North Dakota at a temperature of -35°C to a volume of 3.0 L. The pressure rema
iragen [17]

3.75 litres is the volume of the balloon indoors at a temperature of 25°C.

Explanation:

Data given:

initial temperature of the gas in balloon  = -35°C or 238.15 K

initial volume = 3 litres

final temperature = 25 °C  or 298.15 K

final volume =?

pressure remains constant

From the data given when pressure is constant Charles' law is applied.

\frac{V1}{T1} = \frac{V2}{T2}

Rearranging the equation to know the final volume of the gas in balloon

V2 = \frac{V1T2}{T1}

V2 = \frac{3 X 298.15}{238.15}

V2 = 3.75 Litres

when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.

7 0
3 years ago
Read 2 more answers
The solubility of nitrogen gas at 25°C and a nitrogen pressure of 522 mmHg is 4.7 × 10 –4 mol/L. What is the value of the Henry'
Anestetic [448]

Answer:

6.8 × 10⁻⁴ mol/L.atm

Explanation:

Step 1: Given data

Solubility of nitrogen gas at 25°C (S): 4.7 × 10⁻⁴ mol/L

Partial pressure of nitrogen gas (P): 522 mmHg

Step 2: Convert the partial pressure of nitrogen to atm

We will use the relationship 1 atm = 760 mmHg.

522mmHg \times \frac{1atm}{760mmHg} = 0.687atm

Step 3: Calculate the value of the Henry's Law constant (k)

We will use Henry's law.

S = k \times P\\k = \frac{S}{P} = \frac{4.7 \times 10^{-4}mol/L }{0.687atm} = 6.8 \times 10^{-4} mol/L.atm

3 0
4 years ago
Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C
Leno4ka [110]

Explanation:

The reaction equation will be as follows.

    C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)

Using bond energies, expression for calculating the value of \Delta H is as follows.

    \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

On reactant side, from C_{2}H_{6} number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From Cl_{2}; Cl-Cl bonds = 1

On product side, from C_{2}H_{5}Cl number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

  \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

  =[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]            = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0
3 years ago
What is electron configuration of oxygen in its excited state​
timofeeve [1]

Answer:

1 {s}^{2} 2 {s}^{2} 2 {p}^{4}

OR

2 : 6

3 0
3 years ago
Read 2 more answers
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