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Fudgin [204]
3 years ago
11

What symbol is used for the state of water vapor? A. (l) B. (aq) C. (s) D. (g)

Chemistry
2 answers:
lbvjy [14]3 years ago
6 0

Answer:

its D

Explanation:

EleoNora [17]3 years ago
4 0

Answer:

<em>Hiya There! My name is Jay and I'm here to help!</em>

<h3>Question</h3>

What symbol is used for the state of water vapor?

<h3>Answer</h3>

<em>(Option D is correct)</em>

Explanation:

Water vapor is water that is in the form of a vapor, or gas. It is  Also a part of the water cycle.

Therefore, I hope this Helps! :D

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PLEASE HELP DUE IN 30 MINUTES NO LINKS PLEASE ​
hammer [34]

Answer:

B is the correct answer

Explanation:

If this answer is correct plzz mark me as brainliest plzzzz

7 0
3 years ago
What is antimatter?
stepladder [879]
The answer would be <span>c.
Antimatter is made up of neutrons and electrons but no positive particles

Hope this helped</span>
3 0
4 years ago
Read 2 more answers
I need it please !!!
anyanavicka [17]

Answer:

im pretty sure its 2...

Explanation:

if its wrong im sorry

if its right brainliest pls?

6 0
3 years ago
A gas occupies 4.30 Liters at STP. What volume does it occupy at 2.56 atm and 302
laiz [17]

Answer:

V₂ = 1.86 L

Explanation:

Given data:

Initial volume = 4.30 L

Initial pressure = 1 atm

Initial temperature = 273.15 K

Final temperature = 302 K

Final volume =  ?

Final pressure = 2.56 atm

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁ P₂

V₂ = 1 atm ×4.30 L × 302 K / 273.15 K × 2.56 atm

V₂ = 1298.6 atm.L.K / 699.26 K.atm

V₂ = 1.86 L

4 0
3 years ago
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
3 years ago
Read 2 more answers
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