Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer:(-5,-7)
Step-by-step explanation:
Rewrite in Vertex form and use this form to find the vertex (h,k)
Answer:
it is infinitive solutions because if you do the work you'll find that its infinite solutions...bye rate 1 thx rate more if you think i was wrong just kidding ik im right just say if its helpful ...thx
Step-by-step explanation:
Answer:
f(0) = 2
Roots are;
-2 and -1
Step-by-step explanation:
F(0) simply refers to the y-values when x = 0
This is the point at which the graph crosses the y-axis
the value here is 2
To
find the roots of f(x) , we simply find the points at which the plot crosses the x-axis
we have this at x = -2 and x = -1
These are what represents the roots of the equation
