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prohojiy [21]
2 years ago
12

a 5. A bar has a 20 N weight at one end. You have a weight of 15 N to hang somewhere on the bar so that the bar is in equilibriu

m. Where would you hang the 15 N weights on each of these bars? Consider the bar to have no mass.​
Physics
1 answer:
Dmitry_Shevchenko [17]2 years ago
5 0

the answer is a

Explanation:

it's a because 5n time 4 will give u 20n

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