Answer:
Explanation:
length of the wire = L
Potential difference = Vo
Current = I
new length of the wire, L' = L/2
As we know that the resistance of the wire is directly proportional to the length of the wire.
As the length is halved so that the resistance is also halved.
Resistance = Voltage / Current
V = I R
So, Voltage is constant and the resistance is halved so that the current is doubled.
Answer:
Blue
Explanation:
Because, That object absorbs all colours light waves but des not absorbs Blue. So The blue light is reflected because it is not absorbed
Answer:
Explanation:
a. Landing height is
H=1.3m
Velocity of lander relative to the earth is, i.e this is the initial velocity of the spacecraft
u=1.3m/s
Velocity of lander at impact, i.e final velocity is needed
v=?
The acceleration due to gravity is 0.4 times that of the one on earth,
Then, g on earth is approximately 9.81m/s²
Then, g on Mars is
g=0.4×9.81=3.924m/s²
Then using equation of motion for a free fall body
v²=u²+2gH
v²=1.3²+2×3.924×1.3
v²=1.69+10.2024
v²=11.8924
v=√11.8924
v=3.45m/s
The impact velocity of the spacecraft is 3.45m/s
b. For a lunar module, the safe velocity landing is 3m/s
v=3m/s.
Given that the initial velocity is 1.2m/s²
We already know acceleration due to gravity on Mars is g=3.924m/s²
The we need to know the maximum height to have a safe velocity of 3m/s
Then using equation of motion
v²=u²+2gH
3²=1.2²+2×3.924H
9=1.44+7.848H
9-1.44=7.848H
7.56=7.848H
H=7.56/7.848
H=0.963m
The the maximum safe landing height to obtain a final landing velocity of 3m/s is 0.963m
The answer is:
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"longshore drift" .
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