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2 years ago

(08.03 MC)

Mathematics

1 answer:

satela [25.4K]2 years ago

3 0

Answer: The last one

Step-by-step explanation: The data is all between 4 and 7 and there are no gaps. The max is 7 dollars as stated.

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There are four wires which need to be attached to a circuit board. A robotic device will attach the wires. The wires can be atta

bulgar [2K]

Answer: There are 24 possible sequences of assembly.

Step-by-step explanation:

Since we have given that

Number of wires which need to be attached to a circuit board = 4

We need to find the number of possible sequences of assembly that must be tested.

Using multiplication rule of counting we get that,

Number of possible sequences of assembly is given by

$4!\\\\=4\times 3\times 2\times 1\\\\=24$

i.e. there are four choices for the first wire, three choices for the second wire, two choices for the third wire, one choice for the fourth wire.

Hence, there are 24 possible sequences of assembly.

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3 years ago

5. Ms. Peregrino is using her cards to call on

Ira Lisetskai [31]

Answer: 2/34

Step-by-step explanation: there are 2 sticks with the same name and the total number of students are 34 so its 2/34

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2 years ago

Answer this question

PolarNik [594]

Answer:

(0,8)

Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the value of the expression 0.5^10/0.5^7

SIZIF [17.4K]

Answer:

The solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

Step-by-step explanation:

Given the expression

$0.5^{10}\div 0.5^7$

Solving

$\frac{0.5^{10}}{0.5^7}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$\frac{0.5^{10}}{0.5^7}=0.5^{10-7}$

$\mathrm{Subtract\:the\:numbers:}\:10-7=3$

$=0.5^3$

$=0.125$ ∵ $0.5^3=0.125$

Therefore, the solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

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2 years ago

(Edge comparing data sets quiz) what can be made between the two sets of data in the table?

telo118 [61]

Answer: The 1st one I think.

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3 years ago