Question

A 19.5-mL sample of Ba(OH)2 is titrated with HCl. If 28.4 mL of 0.394 M HCl is needed to reach the endpoint, what is the concentration (M) of the Ba(OH)2 solution

Answer 1

The concentration of Ba(OH)₂ IS 0.287 M.

What is concentration?

This is the amount of solute in mol or in gram that will dissolve in 1 dm³ solution.

Equation of the reaction

• Ba(OH)₂+2HCl→ BaCl₂+2H₂O

Formula:

• CaVa/CbVb = Na/Nb................ Equation 1

Where:

• Ca = Concentration of HCl
• Va = Volume of HCl
• Cb = Concentration of Ba(OH)₂
• Vb = Volume of Ba(OH)₂
• Na = number of moles of HCl
• Nb = number of moles of Ba(OH)₂

Make Cb the subject of the equation

• Cb = (CaVaNb)/(NaVb)................... Equation 2

From the equation and the question,

Given:

• Ca = 0.394 M
• Va = 28.4 mL
• Vb = 19.5 mL
• Na = 2
• Nb = 1

Substitute these values into equation 2

• Cb = (0.394×28.4×1)/(2×19.5)
• Cb = 0.287 M.

Hence, The concentration of Ba(OH)₂ IS 0.287 M.

Learn more about concentration here: brainly.com/question/17206790