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olasank [31]
2 years ago
10

A 19.5-mL sample of Ba(OH)2 is titrated with HCl. If 28.4 mL of 0.394 M HCl is needed to reach the endpoint, what is the concent

ration (M) of the Ba(OH)2 solution
Chemistry
1 answer:
Romashka-Z-Leto [24]2 years ago
5 0

The concentration of Ba(OH)₂ IS 0.287 M.

<h3>What is concentration?</h3>

This is the amount of solute in mol or in gram that will dissolve in 1 dm³ solution.

Equation of the reaction

  • Ba(OH)₂+2HCl→ BaCl₂+2H₂O

Formula:

  • CaVa/CbVb = Na/Nb................ Equation 1

Where:

  • Ca = Concentration of HCl
  • Va = Volume of HCl
  • Cb = Concentration of Ba(OH)₂
  • Vb = Volume of Ba(OH)₂
  • Na = number of moles of HCl
  • Nb = number of moles of Ba(OH)₂

Make Cb the subject of the equation

  • Cb = (CaVaNb)/(NaVb)................... Equation 2

From the equation and the question,

Given:

  • Ca = 0.394 M
  • Va = 28.4 mL
  • Vb = 19.5 mL
  • Na = 2
  • Nb = 1

Substitute these values into equation 2

  • Cb = (0.394×28.4×1)/(2×19.5)
  • Cb = 0.287 M.

Hence, The concentration of Ba(OH)₂ IS 0.287 M.

Learn more about concentration here: brainly.com/question/17206790


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Answer:

bonding driven by ionic interactions.

Explanation:

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2 years ago
When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _
olya-2409 [2.1K]

Balancing redox reactions:

Oxygen should be balanced by adding H_{2}O  as needed, while hydrogen should be balanced by adding H^{+}.

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding H_{2}O, H^{+}, and e^{-} in that order, each reaction is brought into equilibrium:

  1. By putting the right number of water (H_{2}O) molecules on the other side of the equation, the oxygen atoms are brought into balance.
  2. By adding H^{+} ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
  3. Total the fees for each side. Add enough electrons (e^{-}) to the more positive side to make them equal. (As a general rule, e^{-} and  H^{+}are nearly always on the same side.)
  4. The e^{-} on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
  5. One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
  6. Now that the equation has been verified, it can be balanced.

Learn more about redox reaction here,

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#SPJ4

7 0
2 years ago
Wat is diffrent from a square and trapisode
Vikki [24]
The main difference between a square and a trapezoid is that a square has two pairs of parallel sides, while a trapezoid only has one
4 0
3 years ago
A series of six solutions was prepared at the given concentrations. Sample A B C D E F Concentration (mM) 50 100 150 200 300 400
ioda

Answer:

300 mM

Explanation:

In order to solve this problem we need to calculate the line of best fit for those experimental values. The absorbance values go in the Y-axis while the concentration goes in the X-axis. We can calculate the linear fit using Microsoft Excel using the LINEST function (alternatively you can write the Y data in one column and X data in another one, then use that data to create a dispersion graph and finally add the line of best fit and its formula).

The <u>formula for the line of best fit for this set of data is</u>:

  • y = 0.005 * x

So now we <u>calculate the value of </u><u><em>x</em></u><u> when </u><u><em>y</em></u><u> is 1.50</u>:

  • 1.50 = 0.005 * x
  • x = 300 mM

7 0
3 years ago
Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
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Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane = x_{1}

and, mole fraction of toulene = x_{2}

Also,        x_{1} + x_{2} = 1

or,            x_{1} = 1 - x_{2}

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 = (1 - x_{2}) \times 1.375 + x_{2} \times 1.497

               1.456 = 1.375 - 1.375x_{2} + 1.497x_{2}

               0.081 = 0.122x_{2}

                   x_{2} = \frac{0.081}{0.122}

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Since,     x_{1} = 1 - x_{2}

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

3 0
3 years ago
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