1.305 × (23+35.5) = 76.34 grams
Answer:
Q = 1379.4 J
Explanation:
Given data:
Mass of water = 22 g
Initial temperature = 18°C
Final temperature = 33°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.
°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33°C - 18 °C
ΔT = 15°C
Q = 522 g ×4.18 J/g.°C× 15°C
Q = 1379.4 J
Answer:
Number of moles = 0.94 mol
Explanation:
Given data:
Number of moles of sodium chloride = ?
Volume of sodium chloride = 1.25 L
Concentration of solution = 0.750 mol/L
Solution:
Formula:
Concentration = number of moles/ volume in L
By putting values.
0.750 mol/L = number of mole / 1.25 L
Number of moles = 0.750 mol/L×1.25 L
Number of moles = 0.94 mol
A) Answer D. Clouds forming high in the atmosphere are referred to as cirrus, cirrostratus, and cirrocumulus.
B) Clouds tend to form at higher altitudes because as<span> air rises, the moisture in it slowly reaches its saturation point and when this happens, tiny crystals of water start to condense and form clouds.
C) Precipitation: Water that falls to the ground from clouds, such as in rain, snow, sleet, or hail.</span>
