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Maksim231197 [3]
2 years ago
15

How does bond order correspond to phase? Use the drawing of MO energy diagram to predict the bond order of [Be2]+ and [Be2]−. De

termined that the bond order of [Be2]+ is (+1/2).
Chemistry
1 answer:
Dima020 [189]2 years ago
6 0
Bond order is less in solid phases (usually 1), intermediate in liquid (2 or 3), and greatest in gases (3). [Be2]+ has a bond order of 1/2 and for [Be2]-, it has a bond order of 0. The bond order for <span>[Be2]+ is calculated by:
(4 bonding e- - 3 nonbonding e-) / 2 = 1/2</span>
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Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

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N is the number of entities

L is the Avogadro's constant which is

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From the question we have

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We have the final answer as

<h3>6 moles</h3>

Hope this helps you

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