Explanation:
It is known that,
Molar mass of Cd = 112.41 g/mol
Standard concentration of Cd = 0.005 mg/L = 
g/L
Hence, we will calculate the molarity as follows.
Molarity = 
= 
M
Equation for the reaction is as follows.
![K_{sp} = [Cd^{2+}][OH^{-}]^{2}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCd%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D%5E%7B2%7D%5D)
![2 \times 10^{-34} = 4.45 \times 10^{-8} \times [OH^{-}]^{2}](https://tex.z-dn.net/?f=2%20%5Ctimes%2010%5E%7B-34%7D%20%3D%204.45%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%5BOH%5E%7B-%7D%5D%5E%7B2%7D)
![[OH^{-}] = 6.7 \times 10^{-4}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%206.7%20%5Ctimes%2010%5E%7B-4%7D)
M
Also,
![[H^{+}] = \frac{10^{-14}}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7B%5BOH%5E%7B-%7D%5D%7D)
= 
= 
Relation between pH and concentration of hydrogen ions is as follows.
pH = ![-log [H^{+}]](https://tex.z-dn.net/?f=-log%20%5BH%5E%7B%2B%7D%5D)
= 
= 10.82
Thus, we can conclude that a minimum pH of 10.82 is necessary to reduce the dissolved cadmium ion concentration to the standard.
The answer is Photosynthesis!
Answer:
1.48×10²⁴ Cu atoms
Explanation:
For this question you need to use Avogadro's number 6.022×10²³atoms.
2.45 moles of Cu ×
= 1.47539×10²⁴ atoms.
The moles cancel out so you are left with atoms.
Since there are 3 significant figures in the question there should be 3 significant figures in your answer, which is 1.48×10²⁴ Cu atoms.
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Molarity of stock solution (M₁) = 15.7 M
- Volume of diluted solution (V₂) = 12 L
- Molarity of diluted solution (M₂) = 0.156 M
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume of the stock solution needed</h3>
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
An educated guess is called estimation
