Answer:
1) q=18414.93 W
2) C=12920$
Explanation:
Given data:
pipe length L=25m
pipe diameter D=100mm =0.1 m
air temperature
=
=25
°C.....= 298.15k
pipe surface temp
=150
°C.....=423.15k
surface emissivity e= 0.8
boiler efficiency η=0.90
natural gas price Cg=$0.02 per MJ
1) Total heat loss and radiation heat loss combined
q=
q=
б(
^4-
^4)]....... (1)
б=5.67×10^-8 W/m^2K^4 (boltzmann constant)
area A =L.Dπ=25×0.1π=7.85 m^2
putting all these values in eq (1)
q=18414.93 W
2) suppose boiler is operating non stop annual energy loss will be
E=q.t
=18414.93.3600.24.365
=5.81×10^11 J
to find furnace energy consumption
Ef =E/η
=6.46×10^5 MJ
annual cost
C=Cg. Ef
=12920$
Answer:
Your question is lacking some information attached is the missing part and the solution
A) AB = AD = BD = 0, BC = LC
AC = 
B) AB = AD = BC = BD = 0
AC = 
Explanation:
A) Forces in all members due to the load L in position A
assuming that BD goes slack from an inspection of Joint B
AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C
B) steps to arrive to the answer is attached below
AB = AD = BC = BD = 0
AC = 
Answer:
a. 3.17*10¹⁹ b. 3.17*10¹⁴
Explanation:
a. Area A = 1cm²
Thickness h = 0.1cm
Energy of photon E = hf=hc/λ
Where f = frequency; c=speed of light; λ=wavelength = 6300Α=6300*10⁻¹⁰;
Planck's constant h = 6.626*10⁻³⁴ joule-seconds; speed of light c = 3*10⁸
Therefore E = (6.626*10⁻³⁴)*3*10⁸/6300*10⁻¹⁰=3.155*10¹⁹J
1Watt of light releases 3.17*10¹⁸ photons per second.
Volume of sample = Area * Thickness = 1*0.1=0.1cm³
Therefore, number of electron hole pairs that are generated per unit volume per unit time = 3.17*10¹⁸/0.1 = 3.17*10¹⁹photon/cm³-s
b. Steady state excess carrier concentration = 3.17*10¹⁹*10μs
=3.17*10¹⁹*10*10⁻⁶
=3.17*10¹⁴/cm³
Answer: None of the above
Explanation:
Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.
Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.
It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.
Therefore, the answer to the question will be "None of the above".
Answer:
Ψ = 10(y^2) + c
<em><u>y = 1.067m</u></em>
Explanation:
since the flow is one dimensional in positive X direction, the only velocity component is in X, which is denoted by u
while u is a function of y
we find the u in terms of y; u varies linearly wih y
we use similiraty to find the relation
32/1.6 =<em>u/y</em>
<em><u>u = 20y</u></em>
<em><u>Ψ = ∫20ydy</u></em>
<em><u>Ψ = 10(y^2) + c</u></em>
<em><u>(b)</u></em>
<em><u>the flow is half below y = 1.6*(2/3)=1.067 m</u></em>
<em><u>this is because at two third of the height of a triangle lies the centroid of triangle. since the velocity profile forms a right angled triangle , its height is 1.6 m . the flow is halved at y = 1.067m</u></em>