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kkurt [141]
3 years ago
13

Compare and contrast arch and beam bridges

Engineering
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0
-beam bridges use simple, vertical posts to suspend a straight, horizontal bridge,

-arch bridges use a curving support structure.
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Consider the following class definitions: class smart class superSmart: public smart { { public: public: void print() const; voi
arsen [322]

Answer:

a) There is no any private member of smart which are public members of superSmart.

Explanation:

5 0
3 years ago
An airplane travels 1000 miles at velocity of 500 miles in every hour. solve for the time it took the plane to arrive.
alukav5142 [94]

Answer:

Time taken by airplane to cover given distance = 2 hour

Explanation:

Given:

Distance cover by airplane = 1,000 miles

Velocity of airplane = 500 miles per hour

Find:

Time taken by airplane to cover given distance

Computation:

Time taken = Distance / Velocity(Speed)

Time taken by airplane to cover given distance = Distance cover by airplane / Velocity of airplane

Time taken by airplane to cover given distance = 1,000 / 500

Time taken by airplane to cover given distance = 2 hour

7 0
3 years ago
Calculate the electroosmotic velocity of an aqueous solution through a glass capillary 5 cm long with a 0.5 mm internal diameter
natita [175]

Answer:

Electroosmotic velocity will be equal to 1.6\times 10^{-4}m/sec

Explanation:

We have given applied voltage v = 100 volt

Length of capillary L = 5 mm = 0.005 m

Zeta potential of the capillary surface \xi =80mV=0.08volt

Dielectric constant of glass is between 5 to 10 here we are taking dielectric constant as \epsilon =10

Viscosity of glass is \eta =10^8

Electroosmotic velocity is given as v_{eo}=\frac{\epsilon \xi }{\eta }\times \frac{v}{L}

v_{eo}=\frac{10\times 0.08 }{10^8 }\times \frac{100}{0.005}=1.6\times 10^{-4}m/sec

So Electroosmotic velocity will be equal to 1.6\times 10^{-4}m/sec

8 0
4 years ago
I need this asap thank you :) plzzzzz When the spring on a mousetrap car is fully unwound, the force acting on the car is _____.
Usimov [2.4K]

Answer:  (only friction) the friction lets it keep its speed and not slow down and it creats volocity between the serface of where the mousecar is running and the wheels on the ground

sorry if im wrong i tried my best

6 0
3 years ago
E = 50V, R= 1000 ohms, then I =
Margarita [4]

Explanation:

<em>Current</em><em> </em><em>(</em><em>I)</em><em>=</em><em> </em><em><u>Voltage</u></em><em><u> </u></em><em><u>(</u></em><em><u>V)</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Resistance </em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>0</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1000</em><em>(Ω)</em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>0</em><em>(Ω)</em>

<em>I=</em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em><em> </em><em>(</em><em>Amp)</em><em>. </em><em>Answer</em>

<em>Voltage=</em><em>V</em>

<em>Current</em><em>=</em><em>I</em>

<em>Resistance</em><em>=</em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(Ω)</em><em>=</em><em>Ohm</em>

<em>And </em><em>SI </em><em>unit</em><em> </em><em>of </em><em>current</em><em> </em><em>is</em><em>. </em><em>Ampere(</em><em>Amp)</em><em> </em>

<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>

<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> day</u></em><em><u>.</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em>

8 0
3 years ago
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