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Morgarella [4.7K]
2 years ago
12

A 100-horsepower, three-phase squirrel-cage induction motor is connected to a 240-volt line. A dual-element time-delay fuse is t

o be used as the short-circuit protective device. What is the correct fuse rating
Engineering
1 answer:
antoniya [11.8K]2 years ago
6 0

Based on the National Electrical Code (NEC), a 450-Ampere fuse should be used to protect this polyphase (three-phase) squirrel cage inductor motor.

<u>Given the following data:</u>

  • Power rating = 100-horsepower.
  • Voltage = 240 volt.

<h3>How to determine the correct fuse rating?</h3>

According to Table 430.52 of the National Electrical Code (NEC), a dual-element time delay fuse should be calculated at 175% (1.75) of the full-load current rating for an alternating current (AC) polyphase (three-phase) squirrel cage inductor motor.

In this scenario, the squirrel cage inductor motor didn't list a NEMA design code on its nameplate. Thus, we'll assume that the inductor motor is design B and its fuse rating is given by:

Fuse rating = 248 × 1.75 × 434

In conclusion, the nearest standard fuse size which is above the computed value listed in Section 240.6 of the National Electrical Code (NEC) is 450 amperes.

Read more on National Electrical Code here: brainly.com/question/10619436

#SPJ1

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Answer:

\mu = 0.31

Explanation:

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From figure

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for pure rolling

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from 1 and 2nd equation

mgsin\theta - \frac{2}{3}ma =  ma

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solving for  coefficent of friction we get

\mu = 0.31

4 0
3 years ago
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MA_775_DIABLO [31]

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hope it helps!

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