Question

Assume that 48% of the voters in New York favor a certain legislative proposal. De- termine how many voters in New York need to be sampled so that the magnitude of the difference between the observed relative frequency of those favoring the proposal and the population frequency does not exceed 0.01 with probability 0.99.

Answer 1

The number of the voters in the Newyork need to be sampled will be P=19,782.

What is Probability?

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

It is given in the question that:-

Voters percentage=48%

Margin of error=0.01

Z value at 0.99 = 2.58

By using the formula:-

$\rm M=z\sqrt{\dfrac{\pi(1-\pi)}{n}$

By putting the values:-

$0.01=2.58\sqrt{\dfrac{0.48(1-0.48)}{n}$

$\sqrt{n}=\dfrac{1.40}{0.01}$

$n=19784$

Hence the number of the voters in the Newyork need to be sampled will be P=19,782.

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