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2 years ago

Express 80 as a product of its prime factors, write the prime numbers in accending order

Mathematics

1 answer:

Alex73 [517]2 years ago

4 0

Answer:

80 as a product of prime numbers can be expressed as 2×2×2×2×5

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At a high school there was a survey to find out how many people used different forms of transportation. The study found that 1/4

Alex787 [66]

Answer:

252

Step-by-step explanation:

600X42%=252

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3 years ago

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One store sells milk for $3.00 per gallon. a second store sells milk for $0.80 per quart.if you need two gallons, which store sh

cricket20 [7]

I think the store you should buy from is the $3.00 per gallon.
For the second store, you would have to pay $6.40

Hope this helped!

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3 years ago

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Which is a good comparison of the estimated sum and the actual sum of 7 9/12 + 2 11/12

Verizon [17]

7 + 2 = 9 and 9/12 + 11/12 = 20/12 = 1 8/12 = 1 2/3

9 + 1 2/3 = 10 2/3

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3 years ago

PLEASE HELP!!!!!!!!!!!!! GEOMETRY

lilavasa [31]

Perpendicular, slope is reciprocal and opposite

so answer is C. -7

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3 years ago

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A pilot flew a jet from City A to City B, a distance of 2300 mi. On the return trip, the average speed was 20% faster than the o

Ugo [173]

The speed from City A to City B is 506 miles per hour

Solution:

A pilot flew a jet from City A to City B, a distance of 2300 miles

Distance for trip = 2300 miles

Distance for return trip = 2300 miles

The round-trip took 8 h 20 min

Total time taken for both trips = 8 hour 20 minutes

We know that,

1 hour = 60 minutes

$20 \text{ minutes } = \frac{20}{60} \text{ hour } =\frac{1}{3} \text{ hour }$

Thus, we get,

Total time taken for both trips = $8 + \frac{1}{3} = \frac{24+1}{3} = \frac{25}{3} \text{ hour }$

On the return trip, the average speed was 20% faster than the outbound speed

Let "x" be the speed for out bound trip

Then, x + 20 % of x is the average speed of return trip

$x + 20\% x = x + 0.2x = 1.2x$

Speed for return trip = 1.2x

Time taken is given by formula:

$\text{total time } = \frac{distance}{\text{speed of outbound trip}} + \frac{distance}{\text{speed of return trip}}$

$\frac{25}{3} = \frac{2300}{x} + \frac{2300}{1.2x}\\\\\frac{25x}{3} = \frac{2300 \times 1.2 + 2300}{1.2}\\\\10x = 5060\\\\x = 506$

Thus speed from City A to City B is 506 miles per hour

4 0

4 years ago