Answer:
A.
Step-by-step explanation:
If
AND
y = x + 7, then by the transitive property of equality:

We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:

We can factor out the common x to get:
x(x + 1) = 0
which tells us by the Zero Product Property that either
x = 0 and/or x + 1 = 0 and x = -1
We are expecting 2 solutions for x since this is a second degree polynomial. We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y
y = 0 + 7 so
y = 7 and the coordinate is (0, 7)
y = -1 + 7 so
y = 6 and the coordinate is (-1, 6)
Step 1: Subtract 3x from both sides.
−x+7=−52
Step 2: Subtract 7 from both sides.<span><span><span><span>
−x</span>+7</span>−7</span>=<span><span>−52</span>−7</span></span><span><span>
−x</span>=<span>−59</span></span>
Step 3: Divide both sides by -1.<span><span><span>
<span><span>−x</span><span>−1</span></span></span></span>=<span><span><span><span>−59</span><span>−1</span></span></span></span></span><span>
x=59</span>
Answer:
x = 4/5
y = 1/2
Step-by-step explanation:

so, is just that product, recall to use "<span>3.1416 as the value of π".</span>
Remember when solving inequalities the sign of your inequality reverses when dividing or multiplying negative values. k/-12<15. k>-180 [-180, positive infinity)