This question is incomplete.Here is complete one
Consider a telescope with a small circular aperture of diameter 2.0 centimeters.
If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers
Answer:
λ =492nm
Explanation:
Given Data
diameter=2.0 cm
angular separation=3.0x10^-5 radians
λ=?
Solution
sin(theta) = 1.22 x λ /D
λ=(0.02×sin(3.0×10⁻⁵))/1.22
λ=492nm
Yes since the heavy truck it’s way bigger it can cause more damage to the passenger car
Answer:
Explanation:
Given:
Horizontal distance = 30 m
Note that Wavelength, lambda is the distance between two consecutive crests/troughs. Since,
One boat is at trough, the other is at crest.
The distance between a crest and a trough next to it = lambda/2
Complete cycles = 3 cycles
Time taken for the 3 cycles = 15 s
Vertical distance = 3.8 m
Wavelength, lambda = 2 × horizontal distance
= 2 × 30
= 60 m
Amplitude = vertical distance from the extreme loint to the mid point
= y/2
= 3.8/2
A = 1.9 m
In one cycle = 18/3
= 6 s/cycle
frequency, f = 1/T
= 1/6 = 0.17 Hz
speed,v = lambda × frequency
= 60 × 0.17
= 10 m/s
Are you answering a question or asking? You have already seemed to get the answer, A is the correct answer :I