Create lattice for CaCl2
1 answer:
You might be interested in
Answer:
The new volume is 2415 mL
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.
Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:
P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Having two different states, an initial state and an final state, it is true:
In this case:
- P1= 0.9 atm
- V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
- T1= 195 °C= 468 °K (being 0°C=273°K)
The final state 2 is in STP conditions:
- P2= 1 atm
- V2= ?
- T2= 0°C= 273 °K
Replacing:
Solving:
V2= 2.415 L =2,415 mL
<u><em>The new volume is 2415 mL</em></u>
Hello!
First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL
Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
![[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D%5Cfrac%7B8%20g_%7BCH_3CO_2H%7D%20%20%7D%7B725%20mL%20%2B%207%2C61%20mL%7D%2A%20%5Cfrac%7B1000%20mL%7D%7B1%20L%7D%2A%20%5Cfrac%7B1%20mol_%7BCH_3CO_2H%7D%20%7D%7B60%2C05%20g_%7BCH_3CO_2H%7D%20%7D)
![[CH_3CO_2H]=0,1818 M](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D0%2C1818%20M)
So, the concentration of acetic acid would be 0,1818 M
Have a nice day!
First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL
Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
So, the concentration of acetic acid would be 0,1818 M
Have a nice day!