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Akimi4 [234]
2 years ago
7

Ozone located in the troposphere is _______. A. Considered a pollutant b. Beneficial to living organisms c. Higher in concentrat

ion than ozone in the stratosphere d. All of the above Please select the best answer from the choices provided A B C D.
Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
3 0

The presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.

The atmosphere has been divided into five layers based on the availability and the composition of different elements.

<h3>Troposphere</h3>

The troposphere has been the lowest layer of the atmosphere. It has been closed to the earth surface and provides with clouds and maintain weather.

The gases on the troposphere are used by the organisms for living purpose. The ozone has been a harmful gas for living organisms.

Thus, the presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.

Learn more about troposphere, here:

brainly.com/question/201658

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For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

6 0
3 years ago
Put these events in the correct order
zloy xaker [14]

Answer:

Computer, Microprocessor, Cell Phone, WWW, iPhone

Explanation:

i just did it and got it correct

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A spund waves can travel through ALMOST everything.
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Calculate the PH of a solution 0.030 MH2SO4
Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

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