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Akimi4 [234]
2 years ago
7

Ozone located in the troposphere is _______. A. Considered a pollutant b. Beneficial to living organisms c. Higher in concentrat

ion than ozone in the stratosphere d. All of the above Please select the best answer from the choices provided A B C D.
Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
3 0

The presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.

The atmosphere has been divided into five layers based on the availability and the composition of different elements.

<h3>Troposphere</h3>

The troposphere has been the lowest layer of the atmosphere. It has been closed to the earth surface and provides with clouds and maintain weather.

The gases on the troposphere are used by the organisms for living purpose. The ozone has been a harmful gas for living organisms.

Thus, the presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.

Learn more about troposphere, here:

brainly.com/question/201658

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Which statement is true?
Amiraneli [1.4K]

Answer: c. Matter and energy are conserved in chemical reactions.

Explanation:

According to the law of conservation of matter, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

For every chemical reaction, the law of conservation of energy is applicable which states that the energy of the system remains conserved. Energy can neither be created nor destroyed.  It can be transformed from one form to another.

8 0
2 years ago
Xg 4Na + 15g 02 → 70g 2Na20
aleksley [76]

Answer: 43.125g

Explanation:4Na+ O2=2Na2O

Molar mass: 23. 32. 62. React.mass: 92.

6 0
2 years ago
If a beaker of water and a beaker of acetic acid are at the same elevated temperature, which will cool more quickly to room temp
WINSTONCH [101]
Beaker of water i guess because usually at home when i get out cold water i put in my room and it cools fast for me so..... i think
3 0
3 years ago
Why was 1,2 dichlorobenzene used as the solvent for the diels alder reaction we performed in the lab?
pav-90 [236]

Answer:

1,2 dichlorobenzene was used as the solvent for the diels alder reaction: <em>because the co elimination part of the reaction needs high temp and a high boiling point solvent such as 1,2 dichlorobenzene</em>

Explanation:

Diels-Alder Reaction is a useful synthetic tool to prepare cyclohexane rings. It is a process, which occurs in a single step that consists of a cyclic redistribution of its electrons. The two reagents are bond together through a cyclic transition state in which the two new C-C bonds are formed at the same time. For this to occur, most of the time, it is necessary a high temperature and high-pressure conditions. Since 1,2 dichlorobenzene has a boiling point of 180ºC is a good solvent for this type of reactions.

8 0
2 years ago
The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.
Artist 52 [7]

<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

<u>Explanation:</u>

To calculate the molarity of the solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm

Hence, the osmotic pressure of the solution is 6.70 atm

8 0
3 years ago
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