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3 years ago

Compare the charges and masses of protons neutrons and electrons

1 answer:

8 0

Charges is then there is a negative sign at the right corner of an element it means you have to add, and when it is positive, it means you have to substract

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The teacher shows students a pictorial model of an atom. Which element is

frutty [35]

Answer:

C. Fluorine because the model has 9 protons which is represented by the atomic number

Explanation:

We usually identify an element by the number of protons in them. The number of protons is the atomic number of an atom.

Every atom has a specific number of protons in them.
This number of protons is the atomic number.
According to the periodic law, atoms are arranged on the periodic table based on their atomic number.
The given fluorine atom has 9 protons which represents the atomic number of the atom.
This way, the given number clearly shows the right model for identifying the chemical specie.

4 0

3 years ago

Consider the addition of HBr to 2-pentene. Indicate the re

lana [24]

Answer:

This addition reaction yields 3-BromoPentane and 2-BromoPentane.

Explanation: The reaction is an addition reaction that follows the Markonikoff's principle engaging the electrophillic addition mechnism with electrophile having no lone pair so rearrangement of carbonation is possible. It yields two possible products.

5 0

4 years ago

The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa

Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

6 0

4 years ago

Calculate the mass percent composition of carbon in C4F8

Anon25 [30]

My work to your question

4 0

4 years ago

What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances

belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope mass amu Relative abundance

1 77.9 14.4

2 81.9 14.3

3 85.9 71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9

% abundance of isotope 1 = 14.4% = $\frac{14.4}{100}=0.144$