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3 years ago

mark borrows $2,100 at an 8% simple intrest rate for 9 months. What is the amount he is being charged for borrowing the money

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

Answer:

$ 126

Step-by-step explanation:

9 months is 3/4 of one year

2100 * 3/4 * .08 = 126 dollars interest

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Beau Buys a 3 pound bag of trail mix for a hike. He wants to make 1 ounce bags for his friends with whom he is hiking. How many

qwelly [4]

Beau can make 48 bags of 1 ounce trail mix because a pound equals 16 ounces so you multiply 16 times the 3 pounds she has.

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3 years ago

Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is spread evenly o

Katena32 [7]

If the distribution is uniform between 6 and 12, the probability of being less than 99 is 1 (certainty).

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Perhaps you intend to find the probability that the loss is less than 9 pounds. That value is

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3 years ago

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please help asap! jermiah takes a taxi home from the mall. The taxi company charges $3.00, the rest is in the picture.

goblinko [34]

2.50m + 3.00 = 24.25

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3 years ago

Jasaria can jump rope 42 times in 20 seconds. At this rate, how many times can she jump rope in 1 minute? (20 seconds = 13

Novosadov [1.4K]

Answer:

126 times

Step-by-step explanation:

42 x

--- = ---

20 60

20 x 3 = 60

42 x 3 = 126

4 0

3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

4 years ago