Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
A lot of numbers, equations, etc equal 14.1. Be more specific in your questions. I’m sorry this doesn’t really help but just use this for future reference
The answer to 19b is 35
i’m sorry i don’t know part A
Answer:
The height of the pole is 105ft,
Step-by-step explanation:
Let us call 
the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is 
.
The wire length 
is 14 ft longer than height , hence
.
Thus we get a right triangle with hypotenuse 
, perpendicular , and base 
; therefore, the Pythagorean theorem gives
which upon expanding we get:
further simplification gives
,
which is a quadratic equation with solutions
Since the first solution 
will give the triangle base length of 
which is negative; therefore, we disregard it and pick the solution 
.
Hence, the height of the pole is 105ft.
