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sveticcg [70]
2 years ago
5

Which of these numbers are relatively prime to 51? Select all that apply. da) 84 Ob) 70 Oc) 62 0d) 30

Mathematics
1 answer:
iren2701 [21]2 years ago
6 0

Answer:

  b) 70

  c) 62

Step-by-step explanation:

Numbers are relatively prime when they have no factors in common.

__

The factors of 51 are ...

  51 = 3×17

The factors of the other numbers are ...

  84 = 2²×3×7 . . . . . has a factor of 3 in common with 51

  70 = 2×5×7 . . . . . . no factors in common

  62 = 2×31 . . . . . . . no factors in common

  30 = 2×3×5 . . . . . has a factor of 3 in common with 51

The numbers 70 and 62 are relatively prime to 51.

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2 years ago
How many terms are there in this expression? 3a + b - 4c <br> ——-<br> 3<br> 6<br> 5
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3 years ago
Which fraction represents the decimal 0. ModifyingAbove 1 2 with Bar? One-twelfth StartFraction 3 Over 25 EndFraction StartFract
mestny [16]

The considered decimal number is expressed by the fraction given by: Option C: 4/33

<h3>How to convert from decimal to fraction?</h3>

For conversion from decimal to fraction, we write it in the form a/b such that the result of the fraction comes as the given decimal. Usually, to get the decimal of the form a.bcd, we count how many digits are there after the decimal point (if its finite), then we write 10 raised to that many power as denominator, and the considered number without any decimal point as numerator.

For example:

0.99 = \dfrac{99}{10^2} = \dfrac{99}{100}

(10 raised to power k = 1 followed by k zeroes)

<h3>What is the sum of an infinite geometric series?</h3>

The sum of an infinite geometric series having the initial term "a" and the multiplication per term is done by "r" such that r < 1

is given by

S_{\infty} = \dfrac{a}{1-r}

The series would look like a+ ar+ ar^2+\cdots

For the considered case, the given decimal number is

0.\overline{12} = 0.121212\cdots

We can check all the options available one by one, so as to know which one ends up giving this pattern, or we can use another technique as shown below.

0.12121...  = (0.1 + 0.001 + 0.00001 + ... ) + (0.02 + 0.0002 + 0.000002 + ... )

Each of the two series obtained are geometric series with the multiplication factor as 1/100

Using the sum formula for evaluation of an infinite geometric series, and the fact that initial term of first series is 0.1 and that of second series is 0.02, we get:
0.121212... = \dfrac{0.1}{1-1/100} + \dfrac{0.02}{1 - 1/100} = \dfrac{1}{99/100}(\dfrac{1}{10} + \dfrac{2}{100})\\0.121212...  = \dfrac{100}{99}\times(\dfrac{10}{100} + \dfrac{2}{100})\\\\\\0.121212 ... = \dfrac{12}{99} = \dfrac{4}{33}

Thus, the considered decimal number is expressed by the fraction given by: Option C: 4/33

Learn more about geometric series here:

brainly.com/question/16037289

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