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Dafna11 [192]
2 years ago
6

The blackbody curve for a star named Zeta is shown below. What is the peak wavelength for this star?

Physics
1 answer:
g100num [7]2 years ago
4 0

We are asked for the x coordinate of vertex

Here vertex is present somehow at 850-870nm

The most applicible answer should be 860nm

Option C is correct

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What is the frequency of light with a wavelength of 2.10 × 10-7 m?
andre [41]

Answer:

V = ?

C = 3 × 10^8

wavelength = 2.10 × 10^-7

wavelength = C/V

V = C/wavelength

V = 3 × 10^8/2.10 × 10^-7

V = 1.43 × 10^ 15

5 0
2 years ago
Give a description for each of the following: Polar bear, Caribou, Arctic Fox, Arctic Hare, Snowy Owl, Musk Ox, and Rock Ptarmig
nevsk [136]
Polar Bear-Carnivorous bear 
Caribou-Also known as reindeer, herbivorous 
Arctic Fox-White fox from arctic tundra
Arctic Hare-Polar rabbit, live in North American tundra
Snowy Owl-Large, white owl. Younger= darker plumage
Musk Ox-<span>Arctic mammal of the family Bovidae</span>
Rock Ptarmigan-Medium sized bird
4 0
3 years ago
Read 2 more answers
In electrical work, the symbol W is used to indicate
kirill115 [55]
The question has no answer, sad to say. The symbol W is used as a shortcut of saying "watts" which refers to the unit of power.
The symbol for Voltage = V
The symbol for resistance = R (unit is Ohms)
The symbol of electromagnetic force = N (for Newton)
The symbol or current = I (unit is A for amperes)
5 0
4 years ago
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A plane is flying horizontally at a height of 500 m and a constant speed of 429 km/h when an object is projected downward at an
Strike441 [17]

Answer:  the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h


Explanation:


1) The motion of an object under the action of gravity, when air resistance is neglected is called projectile motion. The path is a curve with the form of  a parabola.


2) The equations that rule that motion are:

  • Horizontal speed:
  • Vx = Vox = constant.
  • In this case it is the same horizontal speed of the plane at the moment when the object was proyected. Vx = 429 km/h.
  • Vertical speed:

         Vy = Voy + gt

         d = yo - Voy×t - gt² / 2

         Vy² = Voy² - 2gd

  • Since, you know Voy =0, g = 9.81 m/s², and d = 500m, you can use the last equation, leading to:

        Vy² = 2(9.81m/s²)(500m) = 9,810 m²/s² ⇒ Vy = √(9,810 m²/s²) = 99 m/s


3) As per definition the average velocity is displacement / time, so you need to find the time to reach the ground.

  • You can use the formula  Vy = Voy + gt
  • Clear t: t = (Vy - Voy) / g = (99 m/s - 0) / 9.81 m/s = 10.1s

  • Average vertical velocity = 500 m / 10.1s = 49.5 m/s.
  • You can convert to km/h: 49.5 m/s × 1km/1,000m × 3600s/h = 178 km/h

4) Conclusion: the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h

8 0
3 years ago
What is the of organizaiton multicellular organsim?
Dmitrij [34]
<span>The five levels of organization in a multicellular organism are cells, tissues, organs, organ systems and organisms.</span>
8 0
3 years ago
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