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grandymaker [24]
3 years ago
13

Which of the following statements best describes energy conservation in heat engines?

Physics
1 answer:
Lorico [155]3 years ago
5 0
B is the correct answer
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What do you know about Russia?​
Naddika [18.5K]

Answer:

Russia is the largest country in the world covering more than 6.6 million square miles. ... Russia also spreads across two continents, covering a portion of Eastern Europe that borders the Ural Mountains. 4. The country's official name is the Russian Federation.

6 0
3 years ago
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A 1500 kg car skids to a halt on a wet road where μk = 0.51. how fast was the car traveling if it leaves 66-m-long skid marks?
djverab [1.8K]

We got coefficient of friction uk = 0.51<span>
Mass m = 1500 kg 
normal force on the car = weight of the car = 1500 * 9.8 N = 14700 N 
and the force of friction on the car, f = uk * normal force = 0.51 * 14700 N = 7497 N 
taking Acceleration a = -f/m = -7497/1500 = -4.998 m/s^2 
Displacement s = 66 m 
Final velocity v = 0 
Initial velocity u = ? 
v^2 = u^2 + 2as 
<span>0 = u^2 - 2 * 4.998 * 66
<span>u = 25.69 m/s </span></span></span>

3 0
3 years ago
Plz I need help !!!!!!!
kumpel [21]
Volume=length*width*hight  2*5*4=40 
p=m/v
p=300/40
p = 7.5 g/cm^<span>3</span>
3 0
3 years ago
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A 4.0 kg model rocket is launched, shooting 50.0 g of burned fuel from its exhaust at an average velocity of 625 m/s. What is th
Scorpion4ik [409]

Answer:

Velocity of rocket will be equal to 7.81 m/sec

Explanation:

We have given mass of the rocket m_1=4kg

Mass of fuel is given m_2=50gram=0.05kg ( As 1 kg is equal to 1000 gram )

Velocity of fuel v_2 = 625 m/sec

We have to find the velocity of rocket v_1

From conservation of momentum we know that initial momentum is equal to final momentum '

So m_1v_1=m_2v_2, here m_1 is mass of rocket v_1 is velocity of rocket m_2 is mass of fuel and v_2 is velocity of fuel

So 4\times v_1=625\times 0.05

v_1=7.81m/sec

So velocity of rocket will be equal to 7.81 m/sec

8 0
4 years ago
A long straight wire has fixed negative charge with a linear charge density of magnitude 4.6 nC/m. The wire is to be enclosed by
Semmy [17]

Answer: -33.3 * 10^9 C/m^2( nC/m^2)

Explanation: In order to solve this problem we have to use the gaussian law, the we have:

Eoutside =0 so teh Q inside==

the Q inside= 4.6 nC/m*L + σ *2*π*b*L where L is the large of the Gaussian surface and b the radius of the shell.

Then we simplify and get

σ= -4.6/(2*π*b)= -33.3 nC/m^2

7 0
3 years ago
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