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grandymaker [24]
3 years ago
13

Which of the following statements best describes energy conservation in heat engines?

Physics
1 answer:
Lorico [155]3 years ago
5 0
B is the correct answer
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2. Draw a ray diagram that shows the image
Lunna [17]

you have to draw diagram

6 0
3 years ago
what is the difference between kinetic energy and random motion of a cylider of oxygen carried by a car and one standing on a pl
pochemuha

Answer:

See explanation below

Explanation:

If we are talking about the kinetic energy of the cylinder of oxygen:

The kinetic energy possessed by any object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

In this case, we have one cylinder carried by a car and one standing on a platform: this means that the speed of the cylinder carried by the car will be different from zero (and so also its kinetic energy will be different from zer), while the speed of the cylinder standing on the platform will be zero (and so its kinetic energy also zero). Therefore, the kinetic energy of the cylinder carried by the car will be larger than that standing on a platform.

Instead, if we are talking about the kinetic energy due to the random motion of the molecules of oxygen inside the cylinder:

The kinetic energy of the molecules in a gas is directly proportional to the absolute temperature of the gas:

K=\frac{3}{2}kT

where k is called Boltzmann constant and T is the absolute temperature of the gas. Therefore, we see that K does not depend on whether the gas is in motion or not, but only on its temperature - therefore, in this case there is no difference between the kinetic energy of the cylinder carried by the car and that standing on the platform (assuming they are at the same temperature)

6 0
3 years ago
Answer ASAP:
Artemon [7]
I think its B

maybe D

5 0
3 years ago
Read 2 more answers
Which atom is most likely to accept the electrons to form from an ionic bond
Mekhanik [1.2K]

a nonmetal with the amount of valence electrons that will complete atom

5 0
3 years ago
The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of
Effectus [21]

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

<h3>Volume of molybdenum</h3>

V = (zm/ρN)

where;

  • z is 2 for cubic unit cell
  • m is mass of the molybdenum
  • ρ is density of the molybdenum

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

<h3>Edge length of the unit cell</h3>

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

Learn more about edge length here:

brainly.com/question/16673486

#SPJ1

4 0
2 years ago
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