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Andreyy89
2 years ago
13

SOMEONE WHO KNOWS AND CAN HELP WITH ACCELERATION AND VELOCITY PLEASE HURRY HELP

Physics
1 answer:
White raven [17]2 years ago
4 0

To find accerleration the formula is force divided by mass the unit for it is m/s also

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The energy levels of a particular quantum object are -11.7 eV, -4.2 eV, and -3.3 eV. If a collection of these objects is bombard
gogolik [260]

To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.

By definition the energy balance is simply given by the change between the two states:

|\Delta E_{ij}| = |E_i-E_j|

Our states are given by

E_1 = -11.7eV

E_2 = -4.2eV

E_3 = -3.3eV

In this way the energy balance for the states would be given by,

|\Delta E_{12}| = |E_1-E_2|\\|\Delta E_{12}| = |-11.7-(-4.2)|\\|\Delta E_{12}| = 7.5eV\\

|\Delta E_{13}| = |E_1-E_3|\\|\Delta E_{13}| = |-11.7-(-3.3)|\\|\Delta E_{13}| = 8.4eV

|\Delta E_{23}| = |E_2-E_3|\\|\Delta E_{23}| = |-4.2-(-3.3)|\\|\Delta E_{23}| = 0.9eV

Therefore the states of energy would be

Lowest : 0.9eV

Middle :7.5eV

Highest: 8.4eV

8 0
3 years ago
1. first nuclear reactor
IRISSAK [1]
The correct matches are as follows:

<span>1. first nuclear reactor 
</span>Fermi - an italian physicist who made the first nuclear reactor<span>
2. </span>1/0 η<span>
 </span>atomic mass <span>
3. decaying nuclei 
</span>fission<span> - nuclear reaction from a heavy elements to lighter elements
4. number of neutrons and protons 
</span>neutron <span>
5. builds heavier elements 
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6. discovered radioactivity 
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7. unit of radiation 
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7 0
3 years ago
Read 2 more answers
A 15kg hoop with a radius of 3 m is rolling at on a level surface when it reaches a 25 degree incline. If it reaches a height of
dimulka [17.4K]

The initial velocity of the hoop is determined as 8.854 m/s.

<h3>Conservation of energy</h3>

The initial velocity of the hoop can be determined from the principle of conservation of energy.

Final potential energy = Initial kinetic energy

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

2gh = v²

√2gh = v

√(2 x 9.8 x 4) = v

8.854 m/s = v

Thus, the initial velocity of the hoop is determined as 8.854 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

#SPJ1

4 0
2 years ago
The speed of a 4-kg ball with a momentum of 12 kg m/s is
alisha [4.7K]

Answer:

3 m/s

Explanation:

The momentum of an obejct is given by

p=mv

where

m is the mass of the object

v is the velocity of the object

For the ball in this problem, we know:

p = 12 kg m/s is the momentum

m=4 kg is the mass

Therefore, we can re-arrange the equation to find v, the velocity of the ball:

v=\frac{p}{m}=\frac{12 kg m/s}{4 kg}=3 m/s

4 0
3 years ago
The magnitude of vector A is 37.0 units and points in the direction 310° counterclockwise from the positive x-axis. Calculate th
S_A_V [24]
First what is an equivalent angle for 310 degrees rotated counter clockwise? -50 degrees. so we're in the fourth quadrant. meaning X must be positive and Y must be negative.

use your sine and cosine functions to get the answers now. we know sine relates to Y so use 37sine(-50) equals about -28.3

cosine relates to X so use 37cos(-50) equals about 23.8
7 0
3 years ago
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