Question

At which temperature will water boil when the external pressure is 17.5 torr

Answer 1

Answer: The temperature required to boil will be 8.6 K

Explanation: The normal boiling point of water is taken as 100 °C

The pressure conditions at this temperature is 1 atm

Now, to calculate the temperature required to boil water present at 17.5 torr, we use Gay-Lussac's Law, which states that the pressure is directly proportional to the temperature at constant volume and number of moles.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Initial conditions:

$P_1=1atm=760torr$

$T_1=100^oC=(100+273)K=373K$

Final conditions:

$P_2=17.5torr$

$T_2=?K$

Putting in above equation, we get

$\frac{760}{373}=\frac{17.5}{T_2}$

$T_2=8.6K$

Answer 2

The temperature of water will boil at one hundred degrees celsius when the external pressure is at 17.5 torr. Essentially, it is based off of the vaporizing of heat, as well as the gas constant. This is a matter of solving a physics equation and breaking down the factors that will affect the boiling point.