The radius of the circle is given to be r = 14.5
Let the center be O. So OB is the radius = 14.5
We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.
So, we can write:
![(14.5)^{2}=10^{2}+OA^{2} \\ \\ OA^{2}=110.25 \\ \\ OA=10.5](https://tex.z-dn.net/?f=%2814.5%29%5E%7B2%7D%3D10%5E%7B2%7D%2BOA%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20%0AOA%5E%7B2%7D%3D110.25%20%5C%5C%20%20%5C%5C%20%0AOA%3D10.5%20%20%20%20)
Thus, the measure of OA = 10.5
OB = OA + AB
14.5 = 10.5 + AB
⇒
AB = 4
Some fractions equivalent to 8/3 are 16/6, 24/9, and 32/12.
Answer:
Yes!
Step-by-step explanation:
Here is a trick. If you add up all of the numbers in the number, and if that is divisible by three, the number is divisible by three. So...
5+3+6+1=15
15 is divisible by 3,
so 5361 is divisible by 3
(if you wanted to know, it is 1787)
Answer:
<h2>x = 5</h2><h2>OB = 36</h2><h2>BE = 54</h2>
Step-by-step explanation:
We know that the medians of the triangle divides in a ratio of 2:1. Therefore we have the equation:
<em>cross multiply</em>
<em>use distributive property a(b + c) = ab + ac</em>
![9x-9=(2)(2x)+(2)(8)](https://tex.z-dn.net/?f=9x-9%3D%282%29%282x%29%2B%282%29%288%29)
<em>add 9 to both sides</em>
<em>subtract 4x from both sides</em>
<em>divide both sides by 5</em>
![\boxed{x=5}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D5%7D)
![OB=9x-9\to OB=9(5)-9=45-9=\boxed{36}](https://tex.z-dn.net/?f=OB%3D9x-9%5Cto%20OB%3D9%285%29-9%3D45-9%3D%5Cboxed%7B36%7D)
![OE=OB:2\to OE=36:2=18\to BE=BO+OE\to BE=36+18=54](https://tex.z-dn.net/?f=OE%3DOB%3A2%5Cto%20OE%3D36%3A2%3D18%5Cto%20BE%3DBO%2BOE%5Cto%20BE%3D36%2B18%3D54)
Here youuuu gooo hope this helpsss