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andrey2020 [161]
3 years ago
8

Determine algebraically whether the function g(x)=x^2 is even odd or neither

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0

g(x) = x^2

g(-x) = (-x)^2 ... replace every x with -x

g(-x) = x^2 ... squaring a negative makes it positive

So because g(x) = g(-x) for every x, this means g(x) is an even function. For polynomials, if every exponent is even, then the entire polynomial is even as well.

Note: if a function is even, then it won't be odd or vice versa unless the function is the zero function. In other words, g(x) = 0 is both even and odd.

julsineya [31]3 years ago
5 0

I think its 2 because its 2 so you will put 2

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Y = x² - 4x + 4
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When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

</span>&#10;\text {Length of AB}=  \sqrt{(4-0)^2 + (4-2)^2} =  \sqrt{16 + 4} = \sqrt{20}  = 4.47 \text{ units}
<span>
Answer: 4.47 units

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