Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
<em>
</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
</em>
<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
</em>
<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
Answer:
+ 11m - 11
Step-by-step explanation:
6m+(m-2)(m+7)+3 = 6m + [ m*m - 14 -2m + 7m] + 3
= 6m + mm - 14 + 5m + 3
= mm + 11m - 11
6m+(m-2)(m+7)+3 = + 11m - 11
Answer:
Step-by-step explanation:
Given
There are 9 people going on a trip
They purchased coach tickets =$160
first class tickets =$1180
total budget to spend = $4500
Let coach tickets=X
So first class tickets=9-x
160x+1180(9-x)=4500
160+10620-1180x=4500
160x-1180x=4500-10620
-1020x=-6120
X=6120/1020
X=6
So answer
Coach tickets=X=6
First class tickets=(9-x)
=3.
Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!
I believe if I'm correct the answer is 2a 3b 4c
0 ? f
Sorry I couldn't figure out the one with the question mark.
