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Svetlanka [38]
2 years ago
9

A capacitor that uses 0. 40- mmmm -thick paper as a dielectric is charged to the maximum sustainable voltage. What is the streng

th of the induced electric field?
Physics
1 answer:
Nonamiya [84]2 years ago
6 0

The maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.

<h3>What is maximum electric field strength?</h3>

The maximum electric field strength above which an insulating material begins to break down and conduct is called its dielectric strength.

The dielelectric strength of paper is given as;

E = 16 MV/m = 16 x 10⁶ V/m

Thus, the maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.

Learn more about dielectric strength here: brainly.com/question/27017570?source=archive

#SPJ1

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How many times bigger is the earth than the moon?
liraira [26]
The Earth is around 4 times as big as the moon.
7 0
3 years ago
A skateboarder is moving at 1.75 m/s when she starts going up an incline that causes an acceleration of -0.20 m/s2
Rudiy27

Answer:

Approximately 7.66\; \rm m.

Explanation:

<h3>Solve this question with a speed-time plot</h3>

The skateboarder started with an initial speed of u = 1.75\; \rm m \cdot s^{-1} and came to a stop when her speed became v = 0\; \rm m \cdot s^{-1}. How much time would that take if her acceleration is a = -0.20\; \rm m \cdot s^{-1}?

\begin{aligned} t &= \frac{v - u}{a} \\ &= \frac{0\; \rm m \cdot s^{-1} - 1.75\; \rm m \cdot s^{-1}}{-0.20\; \rm m \cdot s^{-2}} \approx 8.75\; \rm s\end{aligned}.

Refer to the speed-time graph in the diagram attached. This diagram shows the velocity-time plot of this skateboarder between the time she reached the incline and the time when she came to a stop. This plot, along with the vertical speed axis and the horizontal time axis, form a triangle. The area of this triangle should be equal to the distance that the skateboarder travelled while she was moving up this incline until she came to a stop. For this particular question, that area is approximately equal to:

\displaystyle \frac{1}{2} \times 1.75\; \rm m \cdot s^{-1} \times 8.75\; \rm s \approx 7.66\; \rm m.

In other words, the skateboarder travelled 15.3\; \rm m up the slope until she came to a stop.

<h3>Solve this question with an SUVAT equation</h3>

A more general equation for this kind of motion is:

\displaystyle x = \frac{1}{2}\, (u + v) \, t = \frac{1}{2}\, (u + v)\cdot \frac{v - u}{a}= \frac{v^2 - u^2}{2\, a},

where:

  • u and v are the initial and final velocity of the object,
  • a is the constant acceleration that changed the velocity of this object from u to v, and
  • x is the distance that this object travelled while its velocity changed from u to v.

For the skateboarder in this question:

\begin{aligned}x &= \frac{v^2 - u^2}{2\, a}\\ &= \frac{\left(0\; \rm m \cdot s^{-1}\right)^2 - \left(1.75\; \rm m \cdot s^{-1}\right)^2}{2\times \left(-0.20\; \rm m \cdot s^{-2}\right)}\approx 7.66\; \rm m \end{aligned}.

6 0
4 years ago
A speeder passes a parked police car at a constant velocity of 30.0 m/s. The police car starts from rest with a uniform accelera
beks73 [17]
The formula for the speeder should beV1 = d1/t1whereas the formula for the police car is d2  = vo t2 + 1/2 at2^2 where a is equal to 2.44 m/s2. when the overtaking takes place, d1 and d2 are the same, so as t1 and t2
30t = 1/2 *2.44*t2t is equal to 24.59 seconds.d then is equal to 737.70 meters
3 0
3 years ago
DESPERATE WILL GIBE BRAINLIST AND THANKS
const2013 [10]

Answer:

True

Radiometric dating is a process of identifying the age of a material based on known half-lives of decaying radioactive materials found in both organic and inorganic objects. Radiometric dating is often used to determine the age of rocks, bones, and ancient materials.

4 0
3 years ago
What is the relationship between the electric field strength at a point and its distance from the source charge?
Minchanka [31]
<span>The relationship between the electric field strength at a point and its distance from the source charge is inversely proportional. As the electric field strength increases the charges are more closer to each other which means the distance between the is smaller. It is seen by the equation:

E = </span><span>(1/4*pi*epsilon0) (Q/r^2)</span>
5 0
3 years ago
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