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gogolik [260]
3 years ago
5

How many times bigger is the earth than the moon?

Physics
1 answer:
liraira [26]3 years ago
7 0
The Earth is around 4 times as big as the moon.
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The mass of a substance was found to be 8.2 g. By using the water displacement method the volume was found to be 3.6 cm3. Calcul
Vikki [24]
D= M/V

D=8.2/3.6

D= 2.3g/ml
5 0
4 years ago
Read 2 more answers
Place the types of radiation in order of INCREASING mass.
lubasha [3.4K]

Answer & explanation:

  • Gamma Radiation (γ):  Also called gamma rays. Gamma radiation is made of electromagnetic waves, has zero charge and mass, continuously emits heat and has the ability to ionize air and make it conductive of electric current.
  • Beta radiation (β): Beta rays or beta particles, are electrons, negative particles with charge - 1 and mass number 0.
  • Alpha radiation (α): Also called alpha particles or alpha rays, are particles charged by two protons and two neutrons.  They have positive charge +2 and mass number 4.
5 0
4 years ago
How did rutherford’s experiment shape our current model of the atom?
marissa [1.9K]

Answer:

Explanation:

Before the Rutherford's model of the atom, the plum pudding model proposed by J.J Thomson through his experiment using the gas discharge tube was the prevalent structure of the atom known.

Through Thomson, it was widely and popularly believed that the atom is made up of a pool of negatively charged particles.

When Rutherford performed the Alpha scattering experiment using a thing gold foil, he observed that all the alpha particles passed through the thin gold foil and just a few of them were deflected back.

To explain this, the suggested the atomic or nuclear model of that atom in which an atom has a small positively charged center called nucleus where all the mass is concentrated.

Today, the suggestion that an atom is made up of nucleus is highly relevant and still consistent.

6 0
4 years ago
Se dispara un proyectil con una velocidad inicial de 50 m/s y un ángulo de 30°, por encima de la horizontal. Calcular: a) Posici
dmitriy555 [2]

Answer:

a) Posición y velocidad después de los 6s

i) Posición = -26.58m

ii) velocidad = -33.86m/s

b) Tiempo para alcanzar la altura máxima

= 2.55s

c) Alcance horizontal

= 220.7m

Explanation:

a) Posición y velocidad después de los 6s

i) Posición

y = (usinθ)t – 1/2 gt²

u = 50m/s

θ = 30°

g = 9.81m/s²

t = 6s

y = (50 × sin 30)6 - 1/2 × 9.81 × 6²

y = 150 - 176.58

y = -26.58m

ii) velocidad

v = u sinθ–gt

u = 50m/s

θ = 30°

g = 9.81m/s²

t = 6s

v = 50 × sin 30 - 9.81 × 6

v = 25 - 58.86

v = -33.86m/s

b) Tiempo para alcanzar la altura máxima

usinθ /g

u = 50m/s

θ = 30°

g = 9.81m/s²

= 50 × sin 30/ 9.81

= 25/9.81

= 2.5484199796s

≈ 2.55s

c) Alcance horizontal

R = u²sin2θ/g

u = 50m/s

θ = 30°

g = 9.81m/s²

R = 50² ×( sin 2 ×30°) /9.81

R = 220.69964419m

≈ 220.7m

7 0
3 years ago
HELPPPPPPP !!!!!! PLS A 0.050 kg Truck moving right at 0.20 m/s collides with a toy race car weighing 0.015 kg initially at rest
sergejj [24]

Answer:

v_f=0.15\:\mathrm{m/s}

Explanation:

From the Law of Conservation of Momentum, we can write the following equation:

m_1v_1+m_2v_2=m_fv_f

Because the toy car was initially at rest, m_2v_2=0.

Therefore, we can plug in given values and solve for v_f:

m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$} (two significant figures).

6 0
3 years ago
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