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Sidana [21]
3 years ago
11

A car's position in relation to time is plotted on the graph. What can be said about the car during segment B?

Physics
2 answers:
CaHeK987 [17]3 years ago
5 0

we know that

the speed is equal to

speed=\frac{distance}{time}

The slope of the line on the graph is equal to the speed of the car

so

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

<u>the answer is the option B</u>

The car has come to a stop and has zero velocity

Luba_88 [7]3 years ago
3 0

Option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Further Explanation:

According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.

Concept:

Mathematically, <u>the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.</u>

\boxed{\text{slope}=\tan(\theta)}

Here, \theta is the angle made by the segment of graph with x-axis

The slope can also be expressed as:

\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}

 

Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.

The slope of position-time graph gives velocity.  So, by the definition of slope, we have  

{\text{velocity}=\dfrac{\text{change in position}}{{\text{change in time}}}

Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.

Substitute 0 for \text{change in position} in above expression.

\text{Velocity}=0\text{ m/s}

This shows that the speed of the car in the segment B of the graph will be zero as there is no change in the position of the car with respect to time.

Thus, option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Learn More:

1. A highway patrolman traveling at the speed limit is passed by a car brainly.com/question/2456051

2. Head-on collision of the two bodies brainly.com/question/2097915

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Position, car, relation to time, segment B, 80 sec, zero velocity, travelling, faster, graph, position vs time, constant velocity, slope, change in position, change in time.

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Answer:

<em>the smaller particle moves with speed of 8.706 m/s in the opposite direction to the bigger particle.</em>

<em></em>

Explanation:

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<em>According to the conservation of momentum, the total initial momentum of a system must be equal tot the total final momentum of the system.</em>

Initial total momentum of the system = 4.381 kg-m/s (momentum of original particle before splitting)

Final total momentum of the system = Total momentum of the particles after splitting = 5.626 kg-m/s + ( 0.143 kg x V_{B})

where  V_{B}  is the velocity of smaller particle A

final total momentum of the system = 5.626 + 0.143V_{B}

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<em>The negative sign indicates that the smaller particle moves in the opposite direction to the bigger particle</em>

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