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ella [17]
3 years ago
12

what is the displacement of a car with an acceleration of 4.00 m/s2 as it increases its speed from 10.0 m/s to 30.0 m/s ?

Physics
1 answer:
sattari [20]3 years ago
6 0

Answer:

100 m

Explanation:

We can use equation of motion to solve this

{v}^{2}  = u {}^{2}  + 2as \\ 30 {}^{2}  =  {10}^{2}  + 2(4.0)s \\ s = 100m

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A transformer is to be used to provide power for a computer disk drive that needs 6.0 V (rms) instead of the 120 V (rms) from th
Ipatiy [6.2K]

Answer:

N_{2}=20 turns

Explanation:

The given case is a step down transformer as we need to reduce 120 V to 6 V.

number of turns on primary coil N_{P}= 400

current delivered by  secondary coil  I_{S}= 500 mA

output voltage = 6 V (rms)

we know that

I_{p}=\frac{V_{out}}{V_{in}\times I_{s}}

putting values we get

I_{p}=\frac{6}{120\times 0.5}

I_{p}= 0.1 A

to calculate number of turns in secondary

\frac{N_{2}}{400} =\frac{6}{120}

therefore, N_{2}=20 turns

5 0
3 years ago
The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl
Nuetrik [128]
<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

<h3>1)</h3>

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

                        = 0

<h3>2)</h3>

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

                            = 2(cos(24)(3.6))

                            = 6.5775 N

                            ≈ 6.6 N

<em />

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4 0
3 years ago
For numbers 2 and 3, which one is compression and which one is rarefaction?
DENIUS [597]
Compression is above the equilibrium and rarefaction is below
5 0
4 years ago
Two spaceships leave Earth in opposite directions, each with a speed of 0.60c with respect to Earth. (a) What is the SPEED of sp
Studentka2010 [4]

Answer:

The relative speed of 1 relative to 2 is 0.88c

Explanation:

In relativistic mechanics the relative speed between 2 objects moving in different direction is given by

v_{ab}=\frac{v_{a}+v_{b}}{1+\frac{v_{a}v_{b}}{c^{2}}}

Since it is given that

v_{a}=0.6c\\\\v_{b}=0.6c

Applying values in the formula we get

v_{ab}=\frac{0.6c+0.6c}{1+\frac{(0.6c)^{2}}{c^{2}}}\\\\v_{ab}=0.88c

8 0
3 years ago
a ball is thrown straight up with an initial speed 40m/s.a) how high does it go? b) what will be its velocity be in 7 secs?c) ho
Vinil7 [7]

By how much would its speed reading increase with each second of fall? ... Ex 3.24 For a freely falling object dropped from rest, what is its acceleration at the end of the 5th second ... Pb 3.3 A ball is thrown straight up with an initial speed of 30 m/s. How high does it go, and how long is it in the air (neglecting air resistance)?.


4 0
3 years ago
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