The answer to your question is 3 3/4.. i hope its right.
Sorry I am late but the I think it is this, I don’t know the answer but here is what I know. answer is: Imagine a rectangle that has one vertex at the origin and the opposite vertex is A. Now that you can see the image of A(3,4) under the rotation is A’(-4,3). It is easier to rotate the points that lie on the axes, and these help us find the image of A.
POINT: (3,0) (0,4) (3,4)
IMAGE (3,0) (-4,0) (-4,3)
Answer:
C. 17.6
General Formulas and Concepts:
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] tanθ = opposite over adjacent
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle θ = 40°
Opposite Leg = <em>x</em>
Adjacent Leg = 21
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [tangent]:

- [Multiplication Property of Equality] Isolate <em>x</em>:

- Rewrite:

- Evaluate:

- Round:

A. 81
b. no entiendo la pregunta
c. 32
d. 64
e. 81
f. 1000
Radius^2=13, so eqn is x^2+y^2=13