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MrRa [10]
2 years ago
15

What is the value of x?

Mathematics
1 answer:
Alexxx [7]2 years ago
5 0

Answer:

To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.

Step-by-step explanation:

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D because you can’t put a negative over a exponent
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Help me please!!
statuscvo [17]

The question is incomplete without the diagram.

Answer:

Icosahedron + Tetrahedron

Octahedron +Tetrahedron

Step-by-step explanation:

Polyhedron 1: Solid:_Icosahedron__    Number: __1___

                       Solid:_Tetrahedron____     Number: _20____

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8 0
3 years ago
Read 2 more answers
Using all of the digits 1-9 (1, 2, 3, 4, 5, 6, 7, 8, 9) in that order and the operations +, - create 4 different equations with
alexandr1967 [171]

5 + 6 + 89

4 + 7 + 89

24 + 67 + 9

1 + 23 + 67 + 9

7 0
4 years ago
Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

Find the distance BC

substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

Compare the length sides

dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

dAB=dBC

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

8 0
4 years ago
Kindly answer this one. Thank you.​
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦  The midline's length is the average of the lengths of the top and bottom parallel sides.

AL=\frac{OR+CE}{2}

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

x=\frac{9+5}{2}=7

2. AL = <em>m</em> - 4, CE = 15, OR = 17

m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16

3. OR = y + 5, AL = 15, CE = 18

15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12

4 0
3 years ago
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