Answer:
Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.
Step-by-step explanation:
We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.
<u><em>Let </em></u>
<u><em> = sample mean comprehensive strength</em></u>
The z-score probability distribution for sample mean is given by;
Z = 
~ N(0,1)
where, 
= population mean comprehensive strength = 5500 psi
= standard deviation = 100 psi
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( > 4985 psi)
P( > 4985 psi) = P( > 
) = P(Z > -15.45) = P(Z < 15.45)
= <u>0.99999</u>
<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>
Answer:
Acute angles are less than 90 degrees, obtuse angles are more than 90 degrees, and right angles are exactly 90 degrees.Step-by-step explanation:
Answer:
You need to have a labotomy sir
Step-by-step explanation:
Answer:
B | 6
Step-by-step explanation:
First, find the length of the wire by finding the perimeter of the rectangle
2(5) 2(7) = 24
If a square has 4 sides, put 24 as the numerator and 4 as the denominator.
24/4
Now, divide it and you'll get 6, the answer.
|x| = x for x ≥ 0
examples:
|3| = 3; |0.56| = 0.56; |102| = 102
|x| = -x for x < 0
examples:
|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102
--------------------------------------------------------------------------------
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
--------------------------------------------------------------------------------
Put the values of x to the equation of the function h(x):
