For a comparison of the nucleus 5626fe, the density of the nucleus 112 48cd is mathematically given as the same.
n(Cd) / n(Fe)=1
<h3>What is the density of the nucleus 112 48cd?</h3>
Generally, the equation for the density is mathematically given as
d=\frac{A}{4/3}\piR^3
Therefore
n(Cd) / n(Fe) = [A (Cd) / (A Fe) ] * [ R (Fe) / R (Cd)]^3
n(Cd) / n(Fe)= (112 / 56 ) * (1/1.26)3
n(Cd) / n(Fe)=1
In conclusion, The ratio of n(Cd) = n(Fe) is 1, hence same
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brainly.com/question/14010194
The reaction between hydrogen and oxygen to form water is given as:
The balanced reaction is:
According to the balanced reaction,
4 g of hydrogen (
) reacts with 32 g of oxygen (
).
So, oxygen reacted with 29.4 g of hydrogen is:
Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.
Answer:
4 line graph
5 pictograph
10 vertical axis
2 bar graph
8 axis
3 pie chart
6 dependent variable
9 horizontal axis
1 graph
3 independent variable
Explanation:
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