Answer:
8.0356 * 10^-5 moles of NaHCO3
Explanation:
Sulphuric acid = H2SO4
Sodium bicarbonate = NaHCO3
The reaction between both compounds is given by;
2NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
In the reactin above;
2 mol of NaHCO3 neutralizes 1 mol of H2SO4
At stp, 1 mol occupies 22.4 L;
1 mol = 22.4 L = 22400 mL
x mol = 0.9 mL
x = 0.9 / 22400 = 4.0178 * 10^-5 moles of H2SO4
Since 2 mol = 1 mol from the equation;
x mol = 4.0178 * 10^-5
x mol = 2 * 4.0178 * 10^-5
x = 8.0356 * 10^-5 moles of NaHCO3
Answer:
It is not possible to determine the type of chemical reaction that will occur when Ca LiOH → without additional information. The chemical formula Ca LiOH could represent a compound, but without knowing what reactants are present and what products are being formed, it is not possible to classify the reaction. Some possible reactions that could occur involving Ca LiOH include a synthesis reaction, where Ca LiOH is formed from its constituent elements, a decomposition reaction, where Ca LiOH breaks down into its constituent elements, or a substitution reaction, where one or more atoms in Ca LiOH are replaced by other atoms.
Explanation:
It takes more energy to breakdown the bonds
Answer: The distance is slightly less than 3.5 m
Explanation: assuming wall and target are the same thing, and the bullet has constant velocity, the bullet will travel 7 m in half a second, so half that distance is 3.5 m.
In reality, the bullet is decelerating (at an unknown rate) so the distance is slightly less than 3.5 m.
There is also a vertical velocity component, which means it hits the target/wall at an angle. The trajectory is such that it hits the wall above the shooter because the ricochet hits at ~the level at which it left the firearm.
If the wall was absent, the bullet would have described a parabola which brough it back to the initial level after 7m. This could be calculated, but it means that the actual distance between the shooter and the wall is slightly less than 3.5 m
In addition, the collision with the wall is not 100% elastic, so the velocity aftercthe ricochetvis further reduced.
A calculation would be complex because these confounding factors are not completely independent of each other, but all reduce the average velocity and therefore the distance.
Therefore it is only possible to say that the distance was somewhat less than 3.5 m
Answer:
Ionic compounds: They have high melting points and boiling points. That is, ionic compounds are non-volatile.
Covalent compounds: They have usually low melting points and boiling points. That is, covalent compounds are usually volatile.
