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evablogger [386]
2 years ago
13

Will give brainliest to first answer, needed fast.

Mathematics
1 answer:
Alex17521 [72]2 years ago
5 0
\bold{FULL SOLUTION:}

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Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee
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Question

Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?

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Answer:

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Step-by-step explanation:

Step 1

We have to find the Algebraic expressions for the cable companies

Cable company A charges $45 a month for cable plus a $18 installation fee.

Let the number of months be represented as x

Hence, this is represented as:

$45 × x + $18

= 45x + 18

Cable B charges $39 a month for cable plus a $30 fee for installation.

Let the number of months be represented as x

Hence, this is represented as:

$39 × x + $30

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The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?

= Cable company A < Cable company B

= 45x + 18 < 39x + 30

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