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Ludmilka [50]
3 years ago
14

A sample of potassium chlorate (15.0 g) is dissolved in 201 g of water at 70 °c with precautions taken to avoid evaporation of a

ny water. the solution is cooled to 30.0 °c and no precipitate is observed. this solution is __________.
a.hydrated
Chemistry
1 answer:
zlopas [31]3 years ago
4 0
Answer is: unsaturated.
Solubility of potassium chlorate on 70°C is approximately 30 grams in 100 grams of water.
Solubility of potassium chlorate on 70°C is approximately 10 grams in 100 grams of water.
So if dissolve 15 g of potassium chlorate in 201 g of water, there is less salt than it solubility and solution is unsaturated.
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Answer:

B. First order, Order with respect to C = 1

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1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

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4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

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k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

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\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

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Order w.r.t B : Use trials 2 and 5

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\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

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1 = (0.5)^{z}

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