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Ludmilka [50]
3 years ago
14

A sample of potassium chlorate (15.0 g) is dissolved in 201 g of water at 70 °c with precautions taken to avoid evaporation of a

ny water. the solution is cooled to 30.0 °c and no precipitate is observed. this solution is __________.
a.hydrated
Chemistry
1 answer:
zlopas [31]3 years ago
4 0
Answer is: unsaturated.
Solubility of potassium chlorate on 70°C is approximately 30 grams in 100 grams of water.
Solubility of potassium chlorate on 70°C is approximately 10 grams in 100 grams of water.
So if dissolve 15 g of potassium chlorate in 201 g of water, there is less salt than it solubility and solution is unsaturated.
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Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

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Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

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6 0
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25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?
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Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: M_{1} = 0.0023 M,          V_{1} = ?

V_{2} = 15.0 mL,           M_{2} = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL

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