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Yuri [45]
1 year ago
13

What volume of 12M HCI is needed to prepare 250 of 0.20M HCI?

Chemistry
1 answer:
Alchen [17]1 year ago
6 0

Answer: 4.2

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(12)V_{A}=(250)(0.20)\\V_{A}=\frac{(250)(0.20)}{12}=\boxed{4.2}

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Which one of the following exhibits dipole-dipole attraction between molecules?
Maslowich

Answer: No one. All these molecules are nonpolar.

Explanation: Dipole-dipole attractions occur only between polar molecules.  To know if a molecule is polar, you have to observe if their dipole moment (μ) is different from 0. You can do this by observing the vectors of charge in each molecule.

In all the molecules of the alternatives, the overall molecule is nonpolar (the sum of the vectors is equal to 0). So, these molecules are attracted only by induced dipole forces (weak forces that exist between nonpolar molecules).

For F2, this molecule is nonpolar because is composed of equal atoms. So, there isn't an atom which pulls the charge for itself.

8 0
3 years ago
Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo
Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = 90 ( moles of chloroform )

Concentration of solution in water = 10 ( moles of water )

Dissociation constant at 25^oC; K_D = 10

K_D = Concentration of solution in chloroform / Concentration of solution in water

Meaning;

K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }

Since 90 mole is present in chloroform and 10 mole is present in water, Total mole of Caffeine present is 100

Now, we substitute our given values into the equation

10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}  \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

8 0
3 years ago
When air bags inflate, nitrogen gas is formed from sodium azide, along with solid sodium. what reaction category is this?
adell [148]
The answer is
alkaline silocate
7 0
3 years ago
How many grams of KCIO3 will be formed from 3.58g of KCI
blsea [12.9K]

Answer:

5 mols

Explanation:

7 0
3 years ago
Dessert biomes have all of these EXCEPT-
Dmitry_Shevchenko [17]
Answer: B). little wind


Explanation: Deserts have few large animals, fertile soil, and little rainfall but they have lots of wind
7 0
3 years ago
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