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Yuri [45]
2 years ago
13

What volume of 12M HCI is needed to prepare 250 of 0.20M HCI?

Chemistry
1 answer:
Alchen [17]2 years ago
6 0

Answer: 4.2

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(12)V_{A}=(250)(0.20)\\V_{A}=\frac{(250)(0.20)}{12}=\boxed{4.2}

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If 15 L of chlorine reacts at a constant temperature of 298 K and pressure of 9 atm, how many grams of hydrochloric acid (HCl) a
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Answer:400k

Explanation:

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3 years ago
Is mixing butter, granulated sugar, and brown sugar until it's creamy a physical or chemical change and why
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Physical

Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.

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If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog
9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

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8 0
3 years ago
An acid
Arte-miy333 [17]
An acid a. has a high pH in solution.
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4 0
3 years ago
2.0 L of oxygen gas and 8.0 L of nitrogen gas at STP are mixed together. The gaseous mixture is compressed to occupy 2.0 L at 29
otez555 [7]

Answer:

5.5 atm

Explanation:

Step 1: Calculate the moles in 2.0 L of oxygen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

2.0 L × 1 mol/22.4 L = 0.089 mol

Step 2: Calculate the moles in 8.0 L of nitrogen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

8.0 L × 1 mol/22.4 L = 0.36 mol

Step 3: Calculate the total number of moles of the mixture

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Step 4: Calculate the pressure exerted by the mixture

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 0.45 mol × (0.0821 atm.L/mol.K) × 298 K / 2.0 L = 5.5 atm

3 0
3 years ago
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