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4 years ago

What is common to all elements in the same group in the periodic table?

Chemistry

2 answers:

lesantik [10]4 years ago

7 0

They have the same number of outer electrons

Otrada [13]4 years ago

7 0

They have the same number of outer electrons is the right answer hope this helps

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Solid NaCl is produced by the

soldi70 [24.7K]

Answer:

2Na (s) + Cl2 (g) -->2NaCl (s) + heat

Explanation:

7 0

3 years ago

Seasonal Changes of Animals in Florida Seasonal Changes of Animals in Wyoming

Lapatulllka [165]

what is different about these two different foxes is the fox in Florida looks like he is on a diet of plants. The fox in wyoming looks like he has a squirel or some kind of animal in his mouth. Also their environment that they live in is completely different from each other hope it helps

Explanation:

3 0

3 years ago

The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approxi

Novay_Z [31]

Answer:

1.115 g

Explanation:

Applying,

R = R' $2^{n/t}$ ................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/( $2^{n/t}$ )............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/( $2^{23/3.8}$ )

R' = 73.9/ $2^{6.05}$

R' = 1.115 g

6 0

3 years ago

An air-filled balloon has a volume of 225 L at 0.940 atm and 25 °C. Soon after, the pressure changes to 0.990 atm and the temper

lorasvet [3.4K]

Answer:

The right choice is V₂ = 195.7 L

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V: is the volume of the gas in L.

n: is the no. of moles of the gas in mol.

R: is the general gas constant,

T: is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

Knowing that:

V₁ = 225 L , P₁ = 0.940 atm

T₁ = 25 °C + 273 = 298 K

V₂ = ??? L, P₂ = 0.990 atm

T₂ = 0 °C + 273 = 273 K

applying in the above equation

(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂

(0.940 atm * 225 L) / 298 K= (0.990 atm * V₂) / 273 K

V₂ = (0.940 atm * 225 L * 273 K) / (298 K * 0.990 atm)

V₂ = 195.7 L

So, the right choice is:

V₂ = 195.7 L

7 0

3 years ago

The equilibrium constant for the chemical equation N2(g) + 3H2(g) ⇌ 2NH3(g) and Kp=0.174 at 243°C. Calculate the value of Kc for

Mashcka [7]

Answer:

The Kc of this reaction is 311.97

Explanation:

Step 1: Data given

Kp = 0.174

Temperature = 243 °C

Step 2: The balanced equation

N2(g) + 3H2(g) ⇌ 2NH3(g)

Step 3: Calculate Kc

Kp = Kc *(RT)^Δn

⇒ with Kp = 0.174

⇒ with Kc = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 Latm/Kmol

⇒ with T = the temperature = 243 °C = 516 K

⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2

0.174 = Kc (0.08206*516)^-2

Kc = 311.97

The Kc of this reaction is 311.97

3 0

3 years ago