Answer:
How much heat is required to raise the temperature of 25.0 grams of waterfrom 75.0°C to its boiling point?
Explanation:
Answer:
A mixture of two or more substances that are evenly mixed throughout.
Explanation:
This is because a solution shouldn't be chemically bonded, that's called a compound.
Answer:
= 9,593.1 Joules
Explanation:
Heat absorbed by water is equivalent to heat released by copper.
Heat absorbed is given by;
Q = mcΔT
where m is the mass, c is the specific capacity and ΔT is the change in temperature.
Therefore;
Since dnsity of water is 1 g/mL, and specific heat capacity is 4.18 J/g°C while the change in temperature is (75-24) = 51°C.
Heat absorbed by water = 45 g × 4.18 J/g°C × 51
= 9,593.1 Joules
Therefore, the heat released by copper is 9,593.1 Joules
Any polar substances because water is polar and like dissolves in like
Answer:
Explanation:
Hello!
In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:
Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:
Therefore, we plug in to obtain:
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